Answer:
The final kinetic energy of the Helium nucleus (alpha particle) after been scattered through an angle of 120° is
8.00 x 10-13J
Explanation:
In Rutherford Scattering experiment, the collision of the helium nucleus with the gold nucleus is an ELASTIC COLLISION. This means that the kinetic energy is conserved ( The same before and after the collision).
Thus, the final kinetic energy of the helium nucleus is the same as initial kinetic energy (8.00 x 10^-13Joules)
Although, the kinetic energy is converted to potential energy in Coulomb's law equation.
That is,
1/2(mv^2) = (K* q1q2)/r
Where m is the mass of helium nucleus, v is its colliding velocity, k is electrostatic constant, q1 is the charge on helium nucleus, q2 is the charge on gold nucleus, r is impact parameter
The total momentum of the system is 2.14i + 21.27j.
A vector quantity with both direction and magnitude is momentum. Kg m/s (kilogram meter per second) or N s serve as its units (newton second).
The total starting momentum of a system must match the entire final momentum of the system since momentum is a conserved quantity. The overall momentum does not change.
The total momentum of the system is defined as follows:
As momentum is vector quantity and vectors can be added, so, the momentum of a system is given by
P = Pₓ + P'
where Pₓ is the x-component of momentum
P' is the y-component of the momentum
Also, we know that
P=mv
where m is mass
v is velocity
Thus,
P = Pₓ + P'
P = m₁vₓ + m₂v'
vₓ is the x-component of the velocity
v' is the y- component of the velocity
Given, m₁= 3.2kg
m₂ = 2.9kg
Now,
P = 3.2 (2.3i + 4.2j) + 2.9 (-1.8i +2.7j)
P = (7.36i + 13.44j) + (-5.22i + 7.83j)
P = 2.14i + 21.27j
Thus, the total momentum of the given system is 2.14i + 21.27j.
Learn more about the momentum here:
brainly.com/question/4956182
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Given:
Inductance, L = 150 mH
Capacitance, C = 5.00 mF
= 240 V
frequency, f = 50Hz
= 100 mA
Solution:
To calculate the parameters of the given circuit series RLC circuit:
angular frequency, 
= 
a). Inductive reactance, 
is given by:
b). The capacitive reactance, 
is given by:
c). Impedance, Z = 
d). Resistance, R is given by:
e). Phase angle between current and the generator voltage is given by:
a. 46 m/s east
The jet here is moving with a uniform accelerated motion, so we can use the following suvat equation to find its velocity:
where
v is the velocity calculated at time t
u is the initial velocity
a is the acceleration
The jet in the problem has, taking east as positive direction:
u = +16 m/s is the initial velocity
is the acceleration
Substituting t = 10 s, we find the final velocity of the jet:
And since the result is positive, the direction is east.
b. 310 m
The displacement of the jet can be found using another suvat equation
where
s is the displacement
u is the initial velocity
a is the acceleration
t is the time
For the jet in this problem,
u = +16 m/s is the initial velocity
is the acceleration
t = 10 s is the time
Substituting into the equation,
Answer:
The object starts away from the origin and then moves toward the origin at a constant velocity. Next, it stops for one second. Finally, it moves away from the origin at a greater constant velocity.
