Answer:
E = 1440 kJ
Explanation:
It is given that,
Power of a cooker oven is 800 W
Voltage at which it is operated is 230 V
Time, t = 30 minutes = 1800 seconds
We need to find the electrical energy used by the cooker oven. The product of power and time is equal to the energy consumed. So,
So, electrical energy of 1440 kJ is consumed by the cooker oven.
To solve this problem we will apply the concepts related to power as a function of the change of energy with respect to time. But we will consider the energy in the body equivalent to kinetic energy. The change in said energy will be the difference between the two velocity data given by half of the mass. We will first convert the given units into an international system like this
Initial Velocity,
Final Velocity,
Now Power is defined as the change of Energy over the time,
But Energy is equal to Kinetic Energy,
Replacing,
Therefore the correct answer is A.
lever (The things that flick the ball around)
Inclined plane (The hill the ball rolls down)
Wedge (The bumps that stop the ball from rolling certain places)
Answer: i know that ice is denser than water because of the reason why ice is expanding:air. ice has tiny air packets inside that make it bigger than the original state(the state which a substance is at at room temperature.
Explanation:
Iron is an element that has been known in its pure form for at least 5,000 years. The name "iron" comes from the...
The element symbol for iron is Fe, which comes from the Latin word for iron, "ferrum."
Iron is one of the most plentiful elements. It comprises about 5.6 percent of the Earth's crust and almost all of its core
Iron is a transition metal.
Animals and plants require iron. Plants use iron in chlorophyll, the pigment used in photosynthesis. Humans use iron in hemoglobin molecules in blood to allow for the transport of oxygen to tissues throughout the body.
Answer:
a) 210 Ω
b) 21 V
c) 0.07 A, 0.03 V
d) VAE = 7 V
VEB = 14 V
VAF = 9 V
VFB = 12 V
Explanation:
a) 100 Ω and 200 Ω are in series, equivalent = 100 + 200 = 300 Ω,
300 Ω and 400 Ω are in series, equivalent = 300 + 400 = 700 Ω
300 Ω and 700Ω are in parallel, so the equivalent resistance between A and B is R where
1/300 + 1/700 = 1/R, get R = 210 Ω
b) Given I = 0.1 A
so VAB = I * R = 1 * 210 = 21.0 V
c) I₁ + I₂ = I = 0.1, so I₂ = 0.1 - I₁
I₁ * 300 = I₂ * 700
I₁ * 300 = (0.1 - I₁) * 700
get I₁ = 0.07 A, I₂ = 0.1 - I₁ = 0.03 A
d) VAE = I₁ * 100 = 7 V
VEB = I₁ * 200 = 14 V
VAF = I₂ * 300 = 9 V
VFB = I₂ * 400 = 12 V
