Answer:
nerve pathways
Explanation:
It is called Neurogenic Bladder (VN) to any alteration of bladder behavior due to a pathology of the central and / or peripheral nervous system. It may consist of the loss of storage and / or urine disposal capabilities. Thus, a lesion in the upper centers causes variation in storage capacity, but if peripheral innervation is affected, loss of emptying capacity occurs. In the case of patients with spinal cord injury (ML) there are changes in both at the same time.
Answer:
(a)
(b)
1120 N
Explanation:
Change in velocity, 
is given by subtracting the initial velocity from the final velocity and expressed as 
Where v represent the velocity and subscripts f and i represent final and initial respectively. Since the ball finally comes to rest, its final velocity is zero. Substituting 0 for final velocity and the given figure of 8 m/s for initial velocity then the change in velocity is given by
To find 
then we substitute 7 kg for m and -8 m/s for therefore 
(b)
The impact force, F is given as the product of mass and acceleration. Here, acceleration is given by dividing the change in velocity by time ie
Substituting t with 0.05 s then 
Since F=ma then substituting m with 7 Kg we get that F=7*-160=-1120 N
Therefore, the impact force is equivalent to 1120 N
Answer:Water is easily evaporated, and oil and grease will not evaporate.
Explanation:
You have to do the math of each and see which one adds up to 66.5
Answer: The distance is 723.4km
Explanation:
The velocity of the transverse waves is 8.9km/s
The velocity of the longitudinal wave is 5.1 km/s
The transverse one reaches 68 seconds before the longitudinal.
if the distance is X, we know that:
X/(9.8km/s) = T1
X/(5.1km/s) = T2
T2 = T1 + 68s
Where T1 and T2 are the time that each wave needs to reach the sesmograph.
We replace the third equation into the second and get:
X/(9.8km/s) = T1
X/(5.1km/s) = T1 + 68s
Now, we can replace T1 from the first equation into the second one:
X/(5.1km/s) = X/(9.8km/s) + 68s
Now we can solve it for X and find the distance.
X/(5.1km/s) - X/(9.8km/s) = 68s
X(1/(5.1km/s) - 1/(9.8km/s)) = X*0.094s/km= 68s
X = 68s/0.094s/km = 723.4 km
