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HACTEHA [7]
2 years ago
5

A ball thrown vertically upwards from ground

Physics
1 answer:
weqwewe [10]2 years ago
4 0

parabolic motion

\tt t_{max}=\dfrac{2u~sin~\alpha }{g}

\tt h_{max}=\dfrac{u^2sin^2\alpha }{2g}

vertically upwards ⇒ α = 90°⇒sin 90° = 1

\tt 4=\dfrac{2u}{10}\rightarrow u=20~m/s

\tt h_{max}=\dfrac{20^2}{2.10}=\boxed{\bold{20~m}}

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