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HACTEHA [7]
2 years ago
5

A ball thrown vertically upwards from ground

Physics
1 answer:
weqwewe [10]2 years ago
4 0

parabolic motion

\tt t_{max}=\dfrac{2u~sin~\alpha }{g}

\tt h_{max}=\dfrac{u^2sin^2\alpha }{2g}

vertically upwards ⇒ α = 90°⇒sin 90° = 1

\tt 4=\dfrac{2u}{10}\rightarrow u=20~m/s

\tt h_{max}=\dfrac{20^2}{2.10}=\boxed{\bold{20~m}}

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Answer with explanation:

The given vectors in are reduced to their componednt form as shown

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Hence The sum and difference is calculated as

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The direction is given by

\theta =tan^{-1}\frac{r_{y}}{r_{x}}\\\\\theta =tan^{-1}\frac{11.11}{-1.49}=97.64^{o}with positive x axis.

Similarly

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The direction is given by

\theta =tan^{-1}\frac{r_{y}}{r_{x}}\\\\\theta =tan^{-1}\frac{11.11}{24.51}=24.38^{o}with positive x axis.

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