Answer:
a warm air mass is caught between two colder air masses. The colder air moves under the warmer air pushing it up and then moves forward until it meets a mass that is warmer and pushes it up too.
Answer:
A) Gold is an example.
D) There is only one type of substance present.
F) Composed of one type of atom with its own unique properties.
Explanation:
Hello! These are the correct answers! (I took the K12 quiz)
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Answer:
moles B = 2.32 moles
Explanation:
In this case, we can assume that both gases are ideals, so we can use the expression for an ideal gas which is:
PV = nRT
From here, we can calculate the total moles (n) that are in the container, and then, by difference, we can calculate how much we have of gas B.
For this case, we will use R = 0.082 L atm / mol K. Solving for n:
n = PV/RT
n = 5 * 20 / 0.082 * 303
n = 4.02 moles
If we have 4.02 moles between the two gases, and we have 1.70 from gas A, then from gas B we simply have:
Total moles = moles A + moles B
moles B = Total moles - moles A
moles B = 4.02 - 1.70
moles B = 2.32 moles
We have 2.32 moles of gas B
