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4 years ago

Consider this equilibrium constant expression:

Chemistry

2 answers:

My name is Ann [436]4 years ago

5 0

D is the right one

and thats all folks hope this help

alex41 [277]4 years ago

3 0

The answer would be: D. Kb for HS–

Kb is the dissociation constant of an acid/base molecule. The word b in Kb is base, which means the formula should have an OH- ion inside it. Ka would be the opposite of Kb where the formula has H+ ion.
In this question, the formula is: [H2S][OH-]/ [HS-]
Since there are OH- ion. Since H2S is acid and HS- is base, I think it should be Kb for HS–

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What is the easiest way to explain molecular compounds and covalent bonds also adding information about valance electrons?

wlad13 [49]

Answer:

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3 years ago

Calculate the density in g/l of co2 gas at 27 Celsius and 0.500 atm pressure

lesya692 [45]

Answer:

The density of CO₂ gas at 27 Celsius and 0.500 atm is 0.89 $\frac{grams}{L}$

Explanation:

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P*V = n*R*T Equation (A)

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas.

Density allows you to measure the amount of mass in a given volume of a substance. So density is defined as the quotient between the mass of a body and the volume it occupies:

$density=\frac{mass}{volume}$

Being the molar mass of a substance the mass contained in one mole of said substance, the number of moles can be expressed as:

$n=\frac{mass}{molar mass}$ Equation (B)

Replacing in Equation (A):

P*V= $\frac{mass}{molar mass}$ *R*T

Solving to get the definition of density expressed in the equation, you get:

$density=\frac{mass}{V} =\frac{P*molar mass}{R*T}$

Being:

P=0.500 atm
Molar mass CO₂= 44 g/mole

R= 0.082 $\frac{atm*L}{mole*K}$

T= 27 C= 300 K (being 0 C=273 K)

and replacing:

$density=\frac{mass}{V} =\frac{0.500 atm*44 \frac{g}{mole} }{0.082 \frac{atm*L}{mole*K} *300 K}$

you get:

density= 0.89 $\frac{grams}{L}$

The density of CO₂ gas at 27 Celsius and 0.500 atm is 0.89 $\frac{grams}{L}$

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3 years ago

Read 2 more answers

My atomic number is 35.453.

ruslelena [56]

CL
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You wiil find in periodic table :)

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