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lora16 [44]
4 years ago
11

Consider this equilibrium constant expression:

Chemistry
2 answers:
My name is Ann [436]4 years ago
5 0

D is the right one

and thats all folks hope this help



alex41 [277]4 years ago
3 0
The answer would be: <span>D. Kb for HS–
</span>
Kb is the dissociation constant of an acid/base molecule. The word b in Kb is base, which means the formula should have an OH- ion inside it. Ka would be the opposite of Kb where the formula has H+ ion.
In this question, the formula is: [H2S][OH-]/ [HS-]
Since there are OH- ion. Since H2S is acid and HS- is base, I think it should be <span>Kb for HS–
</span>
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ikadub [295]
<h3>Answer:</h3>

0.127 mol Au

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
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<u>Stoichiometry</u>

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<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 25.0 g Au

[Solve] moles Au

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of Au - 196.97 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                     \displaystyle 25.0 \ g \ Au(\frac{1 \ mol \ Au}{196.97 \ g \ Au})
  2. [DA] Multiply/Divide [Cancel out units:                                                          \displaystyle 0.126923 \ mol \ Au

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.126923 mol Au ≈ 0.127 mol Au

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