Question

The formula for a buffer solution contains 1.24% w/v of boric acid. How many milliliters of a 5% w/v boric acid solution should be used to obtain the boric acid needed in preparing 1 L of the buffer solution

Answer 1

Answer:

248 mL of 5% w/v boric acid solution should be used to obtain the solution needed.

 

Explanation:

We can calculate the volume of the 5% w/v boric acid solution needed to prepare the buffer solution 1.24% w/v using the following equation:

$C_{i}V_{i} = C_{f}V_{f}$

Where:

$C_{i}$: is the concentration of the initial solution = 5% w/v

$C_{f}$: is the concentration of the final solution = 1.24% w/v

$V_{i}$: is the volume of the initial solution =?

$V_{f}$: is the volume of the final solution = 1 L

Hence, the volume of the 5% solution is:

$V_{i} = \frac{C_{f}V_{f}}{C_{i}} = \frac{1.24 \%*1 L}{5 \%} = 0.248 L = 248 mL$

Therefore, 248 mL of 5% w/v boric acid solution should be used to obtain the solution needed.

I hope it helps you!