The exact values of the remaining <u>five</u> trigonometric functions of theta are
- sinθ = √3/2
- cosecθ = 2/√3
- cosθ = -1/2
- secθ = -2
- cotθ = -1/√3
Since tanθ = -√3.
The remaining <u>five</u> trigonometric functions of theta are sinθ, cosecθ, cosθ, secθ and cotθ.
The next trigonometric function of θ is cotθ.
cotθ = 1/tanθ
= 1/-√3
= -1/√3.
Also, tan²θ + 1 = sec²θ
Substituting tanθ = -√3 into the equation, we have
(-√3)² + 1 = sec²θ
3 + 1 = sec²θ
sec²θ = 4
secθ = ±√4
secθ = ±2
Since θ is in the quadrant II,
secθ = -2
Also, cosθ = 1/secθ
= 1/-2
= -1/2
Also, cot²θ + 1 = cosec²θ
Substituting cotθ = -1/√3 into the equation, we have
(-1/√3)² + 1 = cosec²θ
1/3 + 1 = cosec²θ
cosec²θ = 4/3
cosecθ = ±√(4/3)
cosecθ = ±2/√3
Since θ is in the quadrant II,
cosecθ = +2/√3
Also, sinθ = 1/cosecθ
= 1/2/√3
= √3/2
So, the exact values of the remaining <u>five</u> trigonometric functions of theta are
- sinθ = √3/2
- cosecθ = 2/√3
- cosθ = -1/2
- secθ = -2
- cotθ = -1/√3.
Learn more about trigonometric functions here:
brainly.com/question/4515552
For this problem,all we have to do is translate the word problem into algebraic equations. The equations are as follows:
L = √100 * x = 10x
W = 1/2*y - 3/2*x
Since A is equal to length times width
A = LW
If L is given, we can find the x. Therefore, we must set the equation where the dependent variable is y and the independent variable is x.
125 = LW
W = 125/L
1/2*y - 3/2*x = 125/10x
10x(1/2*y - 3/2*x) = 125
5xy - 15x² = 125
xy - 3x² = 25
y = (25+3x²)/x
<em>y = 25/x + 3x</em>
C+0.19c
1.19c
Hope this helps :)
Answer:
D-8
Step-by-step explanation:
Got it correct on ed.
Answer:
Step-by-step explanation:
Tom: 90 cookies total 60% were sold
Tom: 90 * 60/100 = 54 cookies
Scott: 150 cookies and 2/3 were sold
Scott: 150 * 2/3 = 300/3 = 100
Dawn: sold 46 cookies
Total Sold = 46 + 100 + 54
Total Sold = 200
Answer
Dawn: % = (46 / 200) * 100 = 23%