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Licemer1 [7]
3 years ago
14

He box-and-whisker plot below shows the distribution of the ages, in years, of the trees in the Gordons' back yard. The title of

the box and whisker plot is, Ages of Trees. The number line is labeled, age, in years, and ranges from 15 to 65. Based on the data shown in the box-and-whisker plot above, what is the interquartile range of the ages, in years, of the trees? Respond in the space provided. If your test is on paper, write your answer on the answer she
Mathematics
1 answer:
sdas [7]3 years ago
4 0

Answer:

IQR = 15

Step-by-step explanation:

Given

I will answer this question with the attached plot

Required

The interquartile range (IQR)

This is calculated using:

IQR = Q_3 - Q_1

On the second attachment, I identified Q1 and Q3 on the plot.

So, we have:

Q_3 = 40

Q_1 = 25

IQR = Q_3 - Q_1

IQR = 40 - 25

IQR = 15

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X/7=-6 so solve for x
IgorC [24]

Answer:x-24

Step-by-step explanation:

Solve for xby simplifying both sides of the equation, then isolating the variable.

4 0
3 years ago
Suppose you have just enough money, in coins, to pay for a gallon of milk priced at $2.40. You have 12 coins, all quarters and d
wel
The answer is
q + d = 12
0.25q + 0.10d = 2.40


q - the number of quarters
d - the number of dimes

You have 12 <span>coins, all quarters and dimes:
q + d = 12

The value of 1 quarter is $0.25.
The value of 1 dime is $0.10.
Therefore, if you want to pay </span>$2.40 you will have q quarters of value $0.25(0.25q) and d dimes of value $0.10d (0.10d).
The second equation is:
0.25q + 0.10d = 2.40
3 0
3 years ago
A log is 20 m long, correct to the nearest metre.
Marat540 [252]

Answer:

222 fence posts

Step-by-step explanation:

Since the log is 20 m long, correct to the nearest metre and has to be cut into fence posts which must be 90 cm long, correct  to the nearest 10 centimetres, there can be x fence posts 90 cm long.

So, we have x × 90 cm = 20 m

x × 0.9 m = 20 m

x = 20 m/0.9 m

x = 222.22

x ≅ 222 fence posts

So, the largest number of fence posts that can possibly be cut from the log is 222 fence posts.

4 0
3 years ago
There are 6 paintings on three walls of a room. If annart gallery has 13 such rooms, how many paintings are there in its collect
SSSSS [86.1K]

Answer: (I think)

78 paintings

Step-by-step explanation:

6 x 13 = 78

3 0
3 years ago
0.6(4-2x)=20.5-(3x+10)
solong [7]

The solution of 0.6(4-2x)=20.5-(3x+10) is x = 4.5

<u>Solution:</u>

Given, expression is 0.6 ( 4 – 2x ) = 20.5 – ( 3x + 10 )

We have to solve the above given equation for x.

Now, take the equation  

\rightarrow 0.6(4-2 x)=20.5-(3 x+10)

We have to use BODMAS rule. BODMAS means sequence of operations which is brackets, order, division, multiplication, addition and then subtraction

On solving the brackets, we get

\rightarrow 0.6 \times 4-0.6 \times 2 x=20.5-3 x-10

Now multiplication is given preference

\rightarrow 2.4-1.2 x=10.5-3 x

\rightarrow 3 x-1.2 x=10.5-2.4

Now subtraction is done

\rightarrow 1.8 \mathrm{x}=8.1

Now division is performed

\rightarrow x=\frac{8.1}{1.8}=4.5

Hence, the value of x is 4.5

5 0
3 years ago
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