Answer:
Number 2 is 3:4.
Number 1 is d.
Step-by-step explanation:
Boxers and collies added together gives you 12:16. Divide them both by 4 and you get 3:4.
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The number of student in class 4 (6) divided by the total number of kids in the entire class (18) gives you 0.33333333333. Multiply that by 100 and it gives you 33.3333333333. As a percentage it is 33 1/2 %
I’m pretty sure it would be the third option, 162
<u>EXPLANATION</u><u>:</u>
Given that
sin θ = 1/2
We know that
sin 3θ = 3 sin θ - 4 sin³ θ
⇛sin 3θ = 3(1/2)-4(1/2)³
⇛sin 3θ = (3/2)-4(1/8)
⇛sin 3θ = (3/2)-(4/8)
⇛sin 3θ = (3/2)-(1/2)
⇛sin 3θ = (3-1)/2
⇛sin 3θ = 2/2
⇛sin 3θ = 1
and
cos 2θ = cos² θ - sin² θ
⇛cos 2θ = 1 - sin² θ - sin² θ
⇛cos 2θ = 1 - 2 sin² θ
Now,
cos 2θ = 1-2(1/2)²
⇛cos 2θ = 1-2(1/4)
⇛cos 2θ = 1-(2/4)
⇛cos 2θ = 1-(1/2)
⇛cos 2θ = (2-1)/2
⇛cos 2θ = 1/2
Now,
The value of sin 3θ /(1+cos 2θ
⇛1/{1+(1/2)}
⇛1/{(2+1)/2}
⇛1/(3/2)
⇛1×(2/3)
⇛(1×2)/3
⇛2/3
<u>Answer</u> : Hence, the req value of sin 3θ /(1+cos 2θ) is 2/3.
<u>also</u><u> read</u><u> similar</u><u> questions</u><u>:</u> If sin Θ = 2/3 and tan Θ < 0, what is the value of cos Θ?
brainly.com/question/12618768?referrer
if cos θ -sin θ =1, find θ cos θ +sin θ?
brainly.com/question/88125?referrer
Answer:
a. 19.68 miles per gallon.
b. 26.32 miles per gallon.
Step-by-step explanation:
Mean gas mileage (μ) = 23.0 mpg
Standard deviation (σ) = 4.9 mpg
In a normal distribution, for any length X, the z-score is determined by the following expression:

In a normal distribution, the 25th percentile (first quartile) of a normal distribution has a corresponding z-score of z = -0.677 and the 75th percentile has a corresponding z-score of z = 0.677
a. The first quartile of the distribution of gas mileage is

19.68 miles per gallon.
b. The third quartile of the distribution of gas mileage is

26.32 miles per gallon.