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2 years ago

Use slopes to determine if the lines 6x + 9y = 2 and 9x + 6y = -3 are perpendicular.

1 answer:

8 0

Answer:

Explanation:

Make the equation into slope-int form:
6x + 9y = 2
9y = -6x + 2
y = (-6/9)x + 2/9
y = (-2/3)x + 2/9

9x + 6y = -3
6y = -9x - 3
y = (-9/6)x - 3/6
y = (-3/2)x - 1/2

In order for a line to perpendicular the slope needs to be an opposite reciprocal of the other. If our first slope is -2/3 then the opposite reciprocal should be 3/2 but, we found out that our second slope is -3/2 not 3/2 therefore, it will not perpendicular.

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Step-by-step explanation:

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= x - 7y - 6

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Find the indefinite integral. (Note: Solve by the simplest method—not all require integration by parts. Use C for the constant o

umka2103 [35]

Answer:

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Step-by-step explanation:

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And 2nd=1

∫▒〖arctan⁡(x).1 dx=arctan⁡(x) ∫▒〖1 dx〗-∫▒〖(derivative of arctan(x))dx∫▒〖1 dx〗〗〗

As we know that

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∫▒〖1 dx〗=x

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Let’s solve ∫▒(1/(1+x^2 ))dx by substitution now

Let 1+x^2=u

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1/2 ∫▒(2xdx/u) =1/2 ln⁡(u)+C

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Putting values in Eq1 we get

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3 years ago

Read 2 more answers

Can you do LCM in division method of 550,750,900 plzz

mr_godi [17]

2 | 550,750,900

2 | 275,375,450

3 | 275,375,225

3 | 275,125,75

5 | 275,125,25

5 | 55,25,5

5 | 11,5,5

11 | 11,1,1

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2 years ago

It's geometry please help.

oksano4ka [1.4K]

Answer:

BC = 22

Step-by-step explanation:

BD = 67

Bc = 3x - 2

CD = 4x + 13

BC + CD = BD (Given)

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3x + 4x -2 + 13 = 67

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7x = 67 - 11

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now instead of x put 8

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BC = 22

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3 years ago