I assume that the parabola in this particular problem is one whose axis of symmetry is parallel to the y axis. The formula we're going to use in this case is (x-h)2=4p(y-k). We know variables h and k from the vertex (1,20) but p is not given. However, we can solve for p by substituting values x and y in the formula with the y-intercept:
(0-1)^2=4p(16-20)
Solving for p, p=-1/16.
Going back to the formula, we can finally solve for the x-intercepts. Simply fill in variables p, h and k then set y to zero:
(x-1)^2=4(-1/16)(0-20)
(x-1)^2=5
x-1=(+-)sqrt(5)
x=(+-)sqrt(5)+1
Here, we have two values of x
x=sqrt(5)+1 and
x=-sqrt(5)+1
thus, the answers are: (sqrt(5)+1,0) and (-sqrt(5)+1,0).
Answer:
<u>Simplify both sides of the equation</u>
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<u>Subtract 2 from both sides</u>
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<u>Divide both sides by 2</u>
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y = 7
x = 4 is a vertical line parallel to the y- axis passing through all points with an x- coordinate of 4
A line perpendicular to x = 4 will be a horizontal line parallel to the x- axis with equation y = c where c is the value of the y- coordinate the line passes through.
line passes through (5 , 7) with y- coordinate 7
The equation is therefore y = 7
Answer:
When raised to the power of 4, the binomial (4 + y) expands to:
Step-by-step explanation:
Answer:
3.5
Step-by-step explanation: