Answer:
Let P be the external point. O be the origin. join O and P get OP and nearest point on the circle from P be A.
Let Q be the point onthe circle in which, tangent make 90° with radius at Q.
PQ = 8 and OQ = 6
we get a right angled triangle PQO right angled at Q.
so, OP^2 = OQ^2 + PQ^2= 8^2 + 6^2 = 64 + 36 =1==
therefore OP =10cm
we need nearest point from P, which is PA
PA = OP - OA= 10 -6=4cm
R=I/Pt
hopefully this helps
Answer:
1996
Step-by-step explanation:
To find the number of terms in an arithmetic sequence, divide the common difference into the difference between the last and first terms, and then add 1.
2008 - 13 = 1995 + 1 = 1996
