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Snezhnost [94]
1 year ago
9

Part A Which graph has the following solution set (-9,10) (-6,5) (0,-5) (3,-10)Part B Write the equation of the graph from part

a.

Mathematics
1 answer:
marysya [2.9K]1 year ago
3 0
\begin{gathered} \text{Let:} \\ (x1,y1)=(-9,10) \\ (x2,y2)=(-6,5) \\ m=\frac{y2-y1}{x2-x1}=\frac{5-10}{-6-(-9)}=\frac{-5}{3}=-\frac{5}{3} \\  \end{gathered}

Using the point-slope equation:

\begin{gathered} y-y1=m(x-x1) \\ y-10=-\frac{5}{3}(x+9) \\ y-10=-\frac{5}{3}x-15 \\ y=-\frac{5}{3}x-5 \end{gathered}

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Solution:

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Given data:

A=2\pi r^2+2\pi r h

Let us determine what is h using given A.

A=2\pi r^2+2\pi r h

Subtract 2\pi r^2 on both sides of the expression.

⇒ A-2\pi r^2=2\pi r^2+2\pi r h-2\pi r^2

⇒ A-2\pi r^2=2\pi r^2-2\pi r^2+2\pi r h

⇒ A-2\pi r^2=2\pi r h

Divide both sides of the expression by 2\pi r.

$\frac{ A-2\pi r^2}{2\pi r }=\frac{2\pi rh }{2\pi r }

$\frac{ A-2\pi r^2}{2\pi r }=h

$h=\frac{ A-2\pi r^2}{2\pi r }

Option C is the correct answer.

Hence $h=\frac{ A-2\pi r^2}{2\pi r }.

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4 years ago
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Answer:

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