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Snezhnost [94]
1 year ago
9

Part A Which graph has the following solution set (-9,10) (-6,5) (0,-5) (3,-10)Part B Write the equation of the graph from part

a.

Mathematics
1 answer:
marysya [2.9K]1 year ago
3 0
\begin{gathered} \text{Let:} \\ (x1,y1)=(-9,10) \\ (x2,y2)=(-6,5) \\ m=\frac{y2-y1}{x2-x1}=\frac{5-10}{-6-(-9)}=\frac{-5}{3}=-\frac{5}{3} \\  \end{gathered}

Using the point-slope equation:

\begin{gathered} y-y1=m(x-x1) \\ y-10=-\frac{5}{3}(x+9) \\ y-10=-\frac{5}{3}x-15 \\ y=-\frac{5}{3}x-5 \end{gathered}

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Step-by-step explanation:

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Igoryamba

Answer:

area of larger circle : 9π = 28.27

area of smaller circle: 4π = 12.57

area of shaded region: 15.71

Step-by-step explanation:

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8 0
3 years ago
If one root is the square of the other in the equation 8+mx+27x²=0,find the value of m​
aleksklad [387]

Answer:

The value of m is -30.

Step-by-step explanation:

Let 27\cdot x^{2}+m\cdot x +8 = 0, we notice that expression is a second order polynomials. We can rearrange the polynomial and use factorization to calculate all roots:

x^{2}+\frac{m}{27}\cdot x + \frac{8}{27} = 0 (1)

-x^{2}-x = \frac{m}{27} (2)

x^{3} = \frac{8}{27} (3)

From (3) we find the least root:

x = \sqrt [3]{\frac{8}{27}}

x = \frac{2}{3}

By (2) we have the value of m:

m = -27\cdot (x^{2}+x)

m = -30

3 0
3 years ago
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It's B) 60

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