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Monica [59]
1 year ago
7

A verbal description of a linear function f is given. Express the function f in the form

Mathematics
1 answer:
Lerok [7]1 year ago
6 0

The linear function g which has a rate of change of -16 and initial value 600 is; g = -16x + 600.

<h3>What is the linear function which is as described?</h3>

It follows from the task content that the linear expression which is as described by the given verbal description is to be determined.

Since the standard slope-intercept form of a linear function is as given; f(x) = ax + b.

Where, a = slope (rate of change) and b = y-intercept (initial value).

Therefore, the required linear function which is as described is;

g = -16x + 600

Read more on linear functions;

brainly.com/question/15602982

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I NEED THAT ANSWER ASAP
Neko [114]

Answer:

12.7

Solving steps:-

d = a√2

d = 9 (1.41)

d = 12.69

d = 12.7

7 0
2 years ago
What equation results from completing the squre and then factoring x^2+10=15
nlexa [21]

For this case we must complete squares:

x ^ 2 + 10x = 15

We add the square of half the coefficient of the term "x",

(\frac {b} {2a}) ^ 2 on both sides of the equation:

x^2+10x+(\frac {10} {2 (1)}) ^ 2 = 25 + 15\\x ^ 2 + 10x + 5 ^ 2 = 25 + 15

According to the perfect square trinomial we have:

(a + b) ^ 2 = a ^2 + 2ab + b ^ 2

Rewriting the expression we have:

a = x\\b = 5\\(x + 5) ^ 2 = 25 + 15\\(x + 5) ^ 2 = 40

ANswer:

(x + 5) ^ 2 = 40

6 0
3 years ago
Does anybody know what this equals ??? 2z + 7m = -4z – 11n
Nonamiya [84]

Answer:

nope sorry

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
9 is 12% of which number?
Ksju [112]
74.7 maybe maybe

as 9 goes up your percent goes up, you would want 12% to go up to 100% so for every 1 that 9 increase 12 increases by 12. 

basically divide 100 by 12 then multiply whatever you get x9

im pretty sure thats my best guess
4 0
4 years ago
Show me how to change this decimal to a fraction.
galben [10]

Answer:

98/99

Step-by-step explanation:

0.98 (both the 9 and 8 repeat)

0.98 (both \:  the  \: 9  \: and  \: 8  \: repeat) =  0.\overline{98}   \\ let \: x = 0.\overline{98}...(1) \\ multiply \: both \: side \: of \: eq \: (1) \: by \: 100 \\ 100x = 98.\overline{98}...(2) \\ equation \: (2) - equation \: (1) \\ 100x - x = 98.\overline{98} - 0.\overline{98} \\ 99x = 98 \\ x =  \frac{98}{99}  \\   \implies  \huge \red{0.\overline{98}} =  \orange{\frac{98}{99}}

5 0
3 years ago
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