Answer:
23, 25, 27
Step-by-step explanation:
It can be convenient to work "consecutive integer" problems by using a variable to represent the middle one.
__
<h3>setup</h3>
Let x represent the middle integer. Then (x-2) is the first of the three odd integers, and (x+2) is the third. The given relation is ...
2(x -2) +3x = 67 +2(x +2)
<h3>solution</h3>
5x -4 = 2x +71 . . . . . simplify
3x = 75 . . . . . . . . add 4-2x
x = 25 . . . . . . . divide by 3
The three integers are 23, 25, 27.
Answer:
3x-y=2
m1=-3/-1
m1=3
Since parallel, m1=m2 so,
m1=m2=3
The slope of straight line passing through the point (6,-1) is
y-(-1)=m2(x-6)
y+1=3(x-6)
Step-by-step explanation:
I don't say you have to mark my ans as brainliest but friend if it has helped you,plz don't forget to thank me....
Answer:
On the graph B, at 0 seconds the graph will be <u>at 
</u>
The graph will be <u>going down</u> until 2 seconds, when the diver reaches her deepest point. At 2 seconds the height of the graph will be -8ft.
Step-by-step explanation:
In graph B we are measuring the distance from the surface, that is we are setting the surface to be y=0. Thus if the diver reaches her deepest point 8ft down, she will be below y=0 and at -8ft.
Thus, in shape the graph B will be similar to graph A, but it will be shifted downed by 8ft.
Answer:
2 units up
Step-by-step explanation:
You're just taking the entire graph of cos(x) and then adding 2 so it moves everything up. If you added 2 to x BEFORE taking the cosine
(like y = cos (x+2) ), then you would shift it left 2. Adding and subtracting from the x moves everything left or right. Adding or subtracting at the end just moves it up and down.
Newton's law of cooling is
k (t₁ - t₂) = -ln (T₁ - T∞ / T₂ - T<span>∞)
Use the two data points in the given to find k.
t = 0, T = 154
t = 10, T = 133
Solution:
k(0 - 10) = - ln (154 - 71/ 133 - 71)
-10k = -0.291716
k = 0.02917 or 0.0292
So now find t when T = 100
0.2917 * ( 0 - t) = -ln (154 - 71 / 100 -71)
- 0.02917t = - 1.0515
t = 36. 05 minutes
to the nearest minute t = 36</span>
