Y/3 + 1/4 = 5/12
4y/12 + 3/12 = 5/12
4y/12 = 2/12
4y = 2
/4 /4
y = 1/2
Therefore y = 1/2
Answer:
<B = 108 degrees
Step-by-step explanation:
<A = <B <u><em> (Alternate Angles are congruent)</em></u>
So,
6x+18 = x+93
=> 6x-x = 93-18
=> 5x = 75
<em>Dividing both sides by 5</em>
=> x = 15
Now,
<B = x+93
=> <B = 15+93
=> <B = 108 degrees
The expression with a rational exponent of the seventh root of x to the third power is x to the three sevenths power ⇒ answer A
Step-by-step explanation:
Let us explain how to change the radical expression as an expression
with a rational exponent
1. Find the number of the root and make it the denominator of the
fraction exponent
2. Find the power of the term under the radical and make it the
numerator of the fraction exponent
Examples:

![\sqrt[3]{x^{n}}=x^{\frac{n}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E%7Bn%7D%7D%3Dx%5E%7B%5Cfrac%7Bn%7D%7B3%7D%7D)
![\sqrt[5]{x^{n}}=x^{\frac{n}{5}}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E%7Bn%7D%7D%3Dx%5E%7B%5Cfrac%7Bn%7D%7B5%7D%7D)
So ![\sqrt[m]{x^{n}}=x^{\frac{n}{m}}](https://tex.z-dn.net/?f=%5Csqrt%5Bm%5D%7Bx%5E%7Bn%7D%7D%3Dx%5E%7B%5Cfrac%7Bn%7D%7Bm%7D%7D)
∵ the radical expression is the seventh root of x to the third power
∵ seventh root = ![\sqrt[7]{}](https://tex.z-dn.net/?f=%5Csqrt%5B7%5D%7B%7D)
∵ x to the third power = x³
∴ seventh root of x to the third power = ![\sqrt[7]{x^{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B7%5D%7Bx%5E%7B3%7D%7D)
Let us change it to the rational exponent
∵ ![\sqrt[m]{x^{n}}=x^{\frac{n}{m}}](https://tex.z-dn.net/?f=%5Csqrt%5Bm%5D%7Bx%5E%7Bn%7D%7D%3Dx%5E%7B%5Cfrac%7Bn%7D%7Bm%7D%7D)
∵ ![\sqrt[7]{x^{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B7%5D%7Bx%5E%7B3%7D%7D)
∴ m = 7 and n = 3
∴
= 
∵
is x to the three sevenths power
∴
is x to the three sevenths power
The expression with a rational exponent of the seventh root of x to the third power is x to the three sevenths power
Learn more:
You can learn more about radical equation is brainly.com/question/7153188
#LearnwithBrainly
Find attached a graph that I constructed.
To do that graph I used Excel.
First I did a table with this set of points:
<span><span><span>height presuure
</span>
<span>
miles psi
</span>
<span>
0
14,7
</span>
<span>
<---- initial data
3.6 7.35
</span>
<span>
<--- increase hegiht 3.6 miles => half pressure
7.2
3.675
</span>
<span>
<---- second increase of 3.6 miles in height
10. 8
1.8375
</span>
<span>
<---- third increase of 3.6 miles in height
14.4
0.91875
</span>
<span>
18 0.459375
</span>
</span></span>