Answer:
c
Step-by-step explanation:
i am a really good guesser and i think it is c
4x+12y=48
12y=48-4x
Y=4-3x
Steps
1.subtract 4x to the other side
2.divide 12 to all numbers
Answer is : y=4-3x
Answer:
see below
Step-by-step explanation:
Dosage= 500 mg
Frequency= twice a day (every 12 hours)
Duration= 10 days
Number of dosage= 10*2= 20
residual drug amount after each dosage= 4.5%
We can build an equation to calculate residual drug amount:
d= 500*(4.5/100)*t= 22.5t, where d- is residual drug, t is number of dosage
After first dose residual drug amount is:
After second dose:
As per the equation, the higher the t, the greater the residual drug amount in the body.
Maximum residual drug will be in the body:
- d= 20*22.5= 450 mg at the end of 10 days
Maximum drug will be in the body right after the last dose, when the amount will be:
Answer: $7,500
Step-by-step explanation:
Use the formula: SI = P(1 + rt)
SI = 5000(1 + 0.05[10])
SI = 5000 + 2500
SI = $7,500
After 10 years, your balance should be $7,500
Answer:
-2
Step-by-step explanation:
Let x be the unknown value
Log₆ ( 1/36) = x
( 1/36) = 36⁻¹ = (6²)⁻¹ = 6⁻²
Log₆ ( 1/36) = Log₆
6⁻² = -2 Log₆
6
Log₆
6 = 1
-2 Log₆
6 = -2(1) = -2
