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Anestetic [448]
1 year ago
9

I need a tutor who can answer more than 1 question.if not im sorry i have to end the session

Mathematics
1 answer:
nirvana33 [79]1 year ago
4 0

Part A.

The area of a triangle is given by the product of its base and the height relative to that base.

Since these triangles have the same base b and same height h, they have the same area.

Part B.

The area of a rectangle or parallelogram is given by the product of base and height. Since these figures have the same base and height, they have the same area.

Part C.

These figures have different shapes, so we can't affirm that they have the same area.

Part D.

The height shown in the image is not the height relative to side b, therefore we can't affirm that the triangles have the same area.

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Please help me please i really need help please
UkoKoshka [18]

Answer:

15 feet wide

Step-by-step explanation:

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If a store sells a packet of gum for R5.50 what will the cost for the gum be if you add the vat​
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How would you answer this?
horsena [70]

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d

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3 years ago
if Hayden had 1224 golden apples and jenny had 1889 golden apple how many would the have all together
harina [27]
So, Hayden has 1224 Apples
Jenny has 1889 Apples. 

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4 0
3 years ago
Tough one!
frosja888 [35]
Imx->0 (asin2x + b log(cosx))/x4 = 1/2 [0/0 form] ,applying L'Hospital rule ,we get

= > limx->0 (2a*sinx*cosx - (b /cosx)*sinx)/ 4x3 = 1/2 => limx->0 (a*sin2x - b*tanx)/ 4x3 = 1/2 [0/0 form],

applying L'Hospital rule again ,we get,

 = > limx->0 (2a*cos2x - b*sec2x) / 12x2 = 1/2

For above limit to exist,Numerator must be zero so that we get [0/0 form] & we can further proceed.

Hence 2a - b =0 => 2a = b ------(A)

limx->0 (b*cos2x - b*sec2x) / 12x2 = 1/2 [0/0 form], applying L'Hospital rule again ,we get,

= > limx->0 b*(-2sin2x - 2secx*secx.tanx) / 24x = 1/2 => limx->0 2b*[-sin2x - (1+tan2x)tanx] / 24x = 1/2

[0/0 form], applying L'Hospital rule again ,we get,

limx->0 2b*[-2cos2x - (sec2x+3tan2x*sec2x)] / 24 = 1/2 = > 2b[-2 -1] / 24 = 1/2 => -6b/24 = 1/2 => b = -2

from (A), we have , 2a = b => 2a = -2 => a = -1

Hence a =-1 & b = -2
7 0
3 years ago
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