T^2 = A^3
T^2 = 2^3
T^2 = 8
Time = sq root (8)
Time =
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2.8284271247
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Assume ladder length is 14 ft and that the top end of the ladder is 5 feet above the ground.
Find the distance the bottom of the ladder is from the base of the wall.
Picture a right triangle with hypotenuse 14 feet and that the side opposite the angle is h. Then sin theta = h / 14, or theta = arcsin 5/14. theta is
0.365 radian. Then the dist. of the bot. of the lad. from the base of the wall is
14cos theta = 14cos 0.365 rad = 13.08 feet. This does not seem reasonable; the ladder would fall if it were already that close to the ground.
Ensure that y ou have copied this problem accurately from the original.
X=6,-6
3x= 18
X=18/3
X= 6,-6
Answer:
Step-by-step explanation:
A. 1.4. B. 2.4. C. 1.2
Answer:
use the distributive property to distribute the 8
-16+16n+3n=40+5n
-16+19n=40+5n
-16=40+5n-19n
-16=40-14n
-14n+40= -16
-14n= -16-40
-14n= -56
n= -56/-14
n= 4
