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d1i1m1o1n [39]
3 years ago
10

Eric buys two plants. One plant is 4 inches tall and grows 2 of an inch per week. Another plant is 3 inches tall and grows

Mathematics
2 answers:
Vlad1618 [11]3 years ago
7 0
It’s Abe hope it helped
Liula [17]3 years ago
3 0
It’s Abe beacuse it grew 7 inch week and 4 tall 2 week.
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BRAINLIEST AND FIVE STARS TO CORRECT ANSWER
Llana [10]
The answer is the first option, <-20, -42>.

We can find this by first finding what -2u would equal by multiplying <5, 6> by -2. This gives us <-10, -12>.

Then we need to find out what 5v is equal to, by multiplying <-2, -6> by 5 to get <-10, -30>.

Now that we know what -2u and 5v are, we can substitute them into the equation and get
<-10, -12> + <-10, -30>, which we can split up into -10 - 10 = -20, and -12 - 30 = -42, so your final answer is <-20, -42>.

I hope this helps!
8 0
3 years ago
The ammunition storage room has 10 feet between the floor and the ceiling. Each box of ammunition is 10 feet tall. Each crate of
KIM [24]

Answer:

the maximum number of crates that can be stacked between the floor and ceiling

\frac{height \hspace{0.1cm} of  \hspace{0.1cm} ammunition \hspace{0.1cm} box}{height \hspace{0.1cm} of  \hspace{0.1cm} each \hspace{0.1cm} crate}  = \frac{10 \hspace{0.1cm}  feet}{12 \hspace{0.1cm}  inches}  =  \frac{10 \times 12  \hspace{0.1cm} inches }{12  \hspace{0.1cm} inches}  = 10 \hspace{0.1cm}  crates

where 1 foot  = 12 inches. SO the answer is that a maximum of 10 crates can be stacked from floor to ceiling.

Step-by-step explanation:

i) the maximum number of crates that can be stacked between the floor and ceiling

\frac{height \hspace{0.1cm} of  \hspace{0.1cm} ammunition \hspace{0.1cm} box}{height \hspace{0.1cm} of  \hspace{0.1cm} each \hspace{0.1cm} crate}  = \frac{10 \hspace{0.1cm}  feet}{12 \hspace{0.1cm}  inches}  =  \frac{10 \times 12  \hspace{0.1cm} inches }{12  \hspace{0.1cm} inches}  = 10 \hspace{0.1cm}  crates

where 1 foot  = 12 inches

3 0
2 years ago
What is the next term in the following constant velocity sequence? 10 cm, 16 cm, 22 cm, ...
Snowcat [4.5K]
Hello!

I believe the next term in the velocity sequence should be 28 cm.
6 0
2 years ago
Read 2 more answers
What is the distance between the points (5.-18) and (8,
romanna [79]

Answer:

\sqrt{10}

Step-by-step explanation:

The horizontal distance from points (5,-18) and (8,-17) is 3 because it is 3 units from 5 to 8.  The vertical distance is 1 since it is one unit from -18 to -17.  Now we can use the equation a^{2}+b^{2}=c^{2} where a=3 and b=1 and c is the distance that you are looking for:

a^{2} +b^{2} =c^{2}\\3^{2} +1^{2} =c^{2}\\9+1=c^{2}\\10=c^{2}\\\sqrt{10}=c

8 0
2 years ago
Read 2 more answers
Need help w this please
rusak2 [61]
Solved using proportions.

8 0
3 years ago
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