Answer:
<em>If statement(1) holds true, it is correct that </em>
<em> is an integer.</em>
<em>If statement(2) holds true, it is not necessarily correct that </em>
<em> is an integer.</em>
<em></em>
Step-by-step explanation:
Given two positive integers
and
.
To check whether
is an integer:
Condition (1):
Every factor of
is also a factor of
.

Let us consider an example:

which is an integer.
Actually, in this situation
is a factor of
.
Condition 2:
Every prime factor of <em>s</em> is also a prime factor of <em>r</em>.
(But the powers of prime factors need not be equal as we are not given the conditions related to powers of prime factors.)
Let


which is not an integer.
So, the answer is:
<em>If statement(1) holds true, it is correct that </em>
<em> is an integer.</em>
<em>If statement(2) holds true, it is not necessarily correct that </em>
<em> is an integer.</em>
<em></em>
A. because is $6 for every month as said in 6x, then an additional 12 for signing up, making 6x + 12 and she wants it to be under $60 so you use the less than sign making 6x+12 <60
I'm not good at math i cant help