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Angelina_Jolie [31]
1 year ago
12

Help pls I would use 2 for this right

Mathematics
1 answer:
kipiarov [429]1 year ago
8 0
<h2>Answer:</h2>

Step-by-step explanation:

yeah

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we have 3 boxes and they are equal to 2 circles, if each circle is equal to 1, what is the value of 1 box?
mario62 [17]

Answer:⬛️=.667 (.66 repeating)

Step-by-step explanation) you can set up the equation:

3x=2y

(using x for squares and y for circles).

we know the value of the circles is 1, so plug 1 in for y

3x=2(1) , simplify

3x=2

now get x by itself by dividing both sides by 3

x=2/3

x=.66

8 0
3 years ago
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PLEASE HELP!!!! The question is in the picture.
oee [108]
2 and 3 are both 58 as well. For 4 do 180-58 because a straight line is 180 degrees.
8 0
4 years ago
Which of the following is the simplified form of fifth root of x times the fifth root of x times the fifth root of x times the f
JulsSmile [24]

Which of the following is the simplified form of [1] fifth root of x times the [2] fifth root of x times [3] the fifth root of x times [4] the fifth root of x?


That's


( \sqrt[5] x)^4 = x^{\frac 4 5}


That looks like the second choice.


6 0
4 years ago
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State the horizontal asymptote of the rational function. For full credit, explain the reasoning you used to find the horizontal
Rzqust [24]

So here are the rules of horizontal asymptotes:

  • Degree of Numerator > Degree of Denominator: No horizontal asymptote
  • Degree of Numerator = Degree of Denominator: y=\frac{\textsf{leading coefficient of numerator}}{\textsf{leading coefficient of denominator}}
  • Degree of Numerator < Degree of Denominator: y = 0

Looking at the rational function, since the degree of the numerator is 2 and the degree of the denominator is 1 (and 2 > 1), this means that <u>this function has no horizontal asymptote.</u>

5 0
3 years ago
10.A noted psychic was tested for ESP. The psychic was presented with 200 cards face down and askedto determine if the card was
lions [1.4K]

Answer:

Step-by-step explanation:

The sample proportion \hat p = \dfrac{50}{200}

\hat p = 0.25

The null hypothesis and the alternative hypothesis:

H_o: p = 0.20  \\ \\  H_1 : p > 0.20

Thus; the test statistics is:

Z = \dfrac{\hat p - p_o}{\dfrac{p_o(1-p_o)}{n} }

Z = \dfrac{0.25 -0.20}{\sqrt{\dfrac{0.20(1-0.20)}{200} }}

Z = \dfrac{0.05}{\sqrt{\dfrac{0.16}{200} }}

Z = \dfrac{0.05}{\sqrt{0.0008 }}

Z = 1.768

P-value = 2 × P(Z< - 1.768)

From the z tables

P-value = 2 × 0.03853

P-value = 0.07706

Thus, the p-value is 0.05 < P-value < 0.10

8 0
3 years ago
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