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alisha [4.7K]
1 year ago
13

Hello! Can you, please, explain how to solve this kind of equation "Find m+n, if P(x) = (2m-4)x^2+(5-n)x+13 is constant polynomi

al".

Mathematics
1 answer:
Salsk061 [2.6K]1 year ago
3 0

The value of m + n from getting the values of m and n from the constant polynomial P(x) = (2m - 4)x² + (5 - n)x + 13 is; 7

<h3>What is a constant polynomial?</h3>

A constant Polynomial is defined as a polynomial is a function of the form f(x) = a

where a is a real number, whose highest degree is zero.

Thus, examples of constant Polynomials are f(x) = 5, g(x) = -11 , h(y) = 7/4

Now, we are given the polynomial expression;

P(x) = (2m - 4)x² + (5 - n)x + 13

From the definition of constant Polynomials, we can say that;

2m - 4 = 0 and 5 - n = 0

Thus;

m = 2 and n = 5

Then, m + n = 2 + 5 = 7

Read more about Polynomial at; brainly.com/question/12700460

#SPJ1

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I might not be understanding what you mean but I think it is by counting 10s. 170,180,190,200,210,220,230,240,250,260,270,280,290,300,310,320,330,410.
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What are the zeros of the function f(x)=-x^2+13x-36
Galina-37 [17]

For this case we have the following function:

f (x) = - x ^ 2 + 13x-36

To find the zeros of the function we make y = 0and solve for "x", then:

0 = -x ^ 2 + 13x-36

We multiply by -1 on both sides of the equation:

0 = x ^ 2-13x + 36

We factor the equation, for this we look for two numbers that, when multiplied, result in 36 and when added, result in -13. These numbers are -9 and -4.

(-9) * (- 4) = 36\\-9-4 = -13

Thus, the factored equation is:

(x-9) (x-4) = 0

Therefore, the roots are:

x_ {1} = 9\\x_ {2} = 4

Answer:

x_ {1} = 9\\x_ {2} = 4

6 0
3 years ago
1. A rectangle is 3/4 as wide as it is long. How
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Answer:

B. 6 inches

Step-by-step explanation:

To find how wide it is, multiply the length by 3/4

8(3/4)

= 6

The width of the rectangle in 6 inches.

So, the correct answer is B. 6 inches

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Yellow cab taxi charges $3.00 flat rate and $0.65 per mile. If Katie has no more than $10 to spend. How many miles can she trave
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Answer:

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Step-by-step explanation:

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6 0
3 years ago
A tank with a capacity of 1600 L is full of a mixture of water and chlorine with a concentration of 0.0125 g of chlorine per lit
Veronika [31]

Answer:

y(t) = 20 [1600^(-5/3)] x (1600-24t)^ (5/3)

Step-by-step explanation:

1) Identify the problem

This is a differential equation problem

On this case the amount of liquid in the tank at time t is 1600−24t. (When the process begin, t=0 ) The reason of this is because the liquid is entering at 16 litres per second and leaving at 40 litres per second.

2) Define notation

y = amount of chlorine in the tank at time t,

Based on this definition, the concentration of chlorine at time t is y/(1600−24t) g/ L.

Since liquid is leaving the tank at 40L/s, the rate at which chlorine is leaving at time t is 40y/(1600−24t) (g/s).

For this we can find the differential equation

dy/dt = - (40 y)/ (1600 -24 t)

The equation above is a separable Differential equation. For this case the initial condition is y(0)=(1600L )(0.0125 gr/L) = 20 gr

3) Solve the differential equation

We can rewrite the differential equation like this:

dy/40y = -  (dt)/ (1600-24t)

And integrating on both sides we have:

(1/40) ln |y| = (1/24) ln (|1600-24t|) + C

Multiplying both sides by 40

ln |y| = (40/24) ln (|1600 -24t|) + C

And simplifying

ln |y| = (5/3) ln (|1600 -24t|) + C

Then exponentiating both sides:

e^ [ln |y|]= e^ [(5/3) ln (|1600-24t|) + C]

with e^c = C , we have this:

y(t) = C (1600-24t)^ (5/3)

4) Use the initial condition to find C

Since y(0) = 20 gr

20 = C (1600 -24x0)^ (5/3)

Solving for C we got

C = 20 / [1600^(5/3)] =  20 [1600^(-5/3)]

Finally the amount of chlorine in the tank as a function of time, would be given by this formula:

y(t) = 20 [1600^(-5/3)] x (1600-24t)^ (5/3)

7 0
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