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motikmotik
1 year ago
13

Given 50g and 27ml find density

Chemistry
1 answer:
Airida [17]1 year ago
5 0

Answer:

1.85g per cubic centimeter (g/cm3

Explanation:

because density=mass/volume, so it will be 50g divide by 27ml =. 1.85g/cm3

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Câu 12. Hiện tượng nào sau đây không phải là sự nóng chảy?
Alik [6]
Mình nghĩ C là đáp án đúng
5 0
3 years ago
How do I solve this problem?
JulijaS [17]
First question. Applying ideal gas equation PV=nRT, P= 101.3 x 10³Pa = 1atm. therefore, 1 x 260 x 10^-3 = n x 0.082 x 294.( Temperature in kelvin=273+21). n = 0.01 moles. Volume of gas at STP= n x 22.4 = 0.01x22.4 = 0.224L. Hope this helps
5 0
3 years ago
Why doesn’t the KHP concentration have to be exactly 0.100M? Explain using complete sentences.
ollegr [7]

Answer:

The answer is in the explanation.

Explanation:

The KHP is an acid used as standard in titrations to find concentration of bases as NaOH.

The reaction that explain this use is:

KHP + NaOH → KNaP + H2O

<em>where 1 mole of KHP reacts per mole of NaOH</em>

That means, at equivalence point of a titration in which titrant is NaOH, the moles of KHP = Moles of NaOH added

With the moles of KHP = Moles of NaOH and the volume used by titrant we can find the molar concentration of NaOH.

The moles of KHP are obtained from the volume and the concentration as follows:

Volume(L)*Concentration (Molarity,M) = moles of KHP

If the concentration is more or less than 0.100M, the moles will be higher or lower. For that reason, we need to know the concentration of KHP but is not necessary to be 0.100M.

8 0
3 years ago
What is the ionic equation for dilute hydrochloric acid and magnesium
Nataly [62]

Answer:

Mg(s) + 2H⁺(aq) ⟶ Mg²⁺(aq) + H₂(g)  

Explanation:

A net ionic equation shows all the ionic substances as ions and shows the correct state of each substance.

7 0
3 years ago
Read 2 more answers
If 2.03 g of oxygen react with carbon monoxide, how many grams of CO2 are formed?
mamaluj [8]

Answer:

The suitable equation for this reaction is

2CO + O₂ -----> 2CO₂

Here, we are given that we have 2 grams of O₂

From the equation, we can see that 2 * Moles of O₂ = Moles of CO₂

Moles of O₂:

2/32 = 1/16 moles

Therefore, the number of moles of CO₂ is twice the moles of O₂

Moles of CO₂ = 2 * 1/16

Moles of CO₂  formed = 1/8 moles

Mass of CO₂  formed = Molar mass of CO₂ * Moles of CO₂

Mass of CO₂  formed = 44 * 1/8

Mass of CO₂  formed = 5.5 grams

Hence, option B is correct

Kindly Mark Brainliest, Thanks!!!

8 0
3 years ago
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