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Mnenie [13.5K]
3 years ago
12

Name some coping skills that can be used besides nicotine vape and or vaping marijuana.

Chemistry
2 answers:
Nadusha1986 [10]3 years ago
8 0
Spend time with your friends or family, being socially active helps me in a lot of things, spend time doing your hobbies..
sdas [7]3 years ago
4 0
Exercise, drinking water, friends, anything that can take your mind off those topics
You might be interested in
You determine that Lauren's EER is 2200 kcal/day. You recommend and intake of 60% CHO, 15% protein, and 25% fat. Approximately h
const2013 [10]

Answer:

The answer to your question is 330 g of CHO

Explanation:

Data

Calories needed = 2200 kcal/day

CHO = 60%

Proteins = 15%

Fats = 25%

Grams of carbohydrates needed = ?

Process

1.- Calculate the number of calories  in 60% of 2200 kcal

                      2200 kcal ----------------  100%

                          x            ---------------      60%

                       x = (60 x 2200) / 100

                       x = 1320 kcal

2.- Calculate the grams of CHO

                       1 g of CHO ---------------- 4 kcal

                       x                 ----------------  1320 kcal

                       x = (1320 x 1) / 4

                       x = 1320/4

                       x = 330 g of CHO

6 0
3 years ago
How many particles are in chemicals
stepan [7]

Answer:

6.022 x 10^23 particles

Explanation:

Chemists have chosen to count atoms and molecules using a unit called the mole (mol), from the Latin moles, meaning “pile” or “heap.”

One mole is 6.022 x 10^23 of the microscopic particles which make up the substance in question.

Hope this helped! :^)

4 0
2 years ago
True or False? SLOW moving water deposits sediment.
wolverine [178]

no probs at all :)







5 pts

7 0
3 years ago
C6H14 reacts with oxygen gas and produces 2 products reaction type of chemical equation​
stepan [7]

Answer: reaction type is combustion

Explanation:

C6H14 + 19/2O2 ==> 6CO2 + 7H2O

7 0
3 years ago
Read 2 more answers
What is the new pressure of 150 mL of a gas that is compressed to 50 mL when the original pressure was 3.0 ATM and the temperatu
Arisa [49]

Answer:

\boxed {\boxed {\sf P_2= 9 \ atm}}

Explanation:

Since the temperature is held constant, we only need to focus on the volume and pressure. We will use Boyle's Law, which states the volume of a gas is inversely proportional to the pressure. The formula is:

P_1V_1=P_2V_2

Originally, the gas had a volume of 150 milliliters and a pressure of 3.0 atmospheres. We can substitute these values into the left side of the equation.

3.0 \ atm * 150 \ mL = P_2V_2

The original gas was compressed to a volume of 50 milliliters, but we don't know the volume.

3.0 \ atm *150 \ mL= P_2 * 50 \ mL

Now, we need to solve for the new pressure (P₂). Multiply on the left side first.

450 \ atm*mL= P_2 * 50 \ mL

Since we are solving for the pressure, we need to isolate the variable. It is being multiplied by 50 mL. The inverse of multiplication is division. Divide both sides by 50 mL.

\frac{450 \ atm*mL}{50 \ mL}= \frac{P_2 * 50 \ mL}{50 \ mL}

\frac{450 \ atm*mL}{50 \ mL}= P_2

The units of milliliters will cancel.

\frac{450 \ atm}{50 }= P_2

9 \ atm =P_2

The new pressure is <u>9 atmospheres.</u>

8 0
3 years ago
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