Answer:
The answer to your question is 330 g of CHO
Explanation:
Data
Calories needed = 2200 kcal/day
CHO = 60%
Proteins = 15%
Fats = 25%
Grams of carbohydrates needed = ?
Process
1.- Calculate the number of calories in 60% of 2200 kcal
2200 kcal ---------------- 100%
x --------------- 60%
x = (60 x 2200) / 100
x = 1320 kcal
2.- Calculate the grams of CHO
1 g of CHO ---------------- 4 kcal
x ---------------- 1320 kcal
x = (1320 x 1) / 4
x = 1320/4
x = 330 g of CHO
Answer:
6.022 x 10^23 particles
Explanation:
Chemists have chosen to count atoms and molecules using a unit called the mole (mol), from the Latin moles, meaning “pile” or “heap.”
One mole is 6.022 x 10^23 of the microscopic particles which make up the substance in question.
Hope this helped! :^)
Answer: reaction type is combustion
Explanation:
C6H14 + 19/2O2 ==> 6CO2 + 7H2O
Answer:

Explanation:
Since the temperature is held constant, we only need to focus on the volume and pressure. We will use Boyle's Law, which states the volume of a gas is inversely proportional to the pressure. The formula is:

Originally, the gas had a volume of 150 milliliters and a pressure of 3.0 atmospheres. We can substitute these values into the left side of the equation.

The original gas was compressed to a volume of 50 milliliters, but we don't know the volume.

Now, we need to solve for the new pressure (P₂). Multiply on the left side first.

Since we are solving for the pressure, we need to isolate the variable. It is being multiplied by 50 mL. The inverse of multiplication is division. Divide both sides by 50 mL.


The units of milliliters will cancel.


The new pressure is <u>9 atmospheres.</u>