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love history [14]
3 years ago
7

How much potential energy an object has depends on the object​

Chemistry
1 answer:
riadik2000 [5.3K]3 years ago
5 0
Yea you’re right. You answered your own question lol
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Give an example of two other body systems that work together and explain how they support each other.
gulaghasi [49]

Answer:

2 examples are cardiovascular and respiratory systems.

7 0
3 years ago
How is helium which is produced by the conversion of hydrogen into energy related to the solar core
qaws [65]
The sun's core is where Hydrogen atoms produce energy as they convert to molecules of Helium. Helium that is produced by the conversion of hydrogen into energy is related to the solar core in the sense that the conversion process produces energy captured in the core. I hope this helps you. 
3 0
3 years ago
Read 2 more answers
A certain radioactive isotope decays at a rate of 0.2​% annually. Determine the ​half-life of this​ isotope, to the nearest year
pychu [463]

Answer:

The half-life of the radioactive isotope is 346 years.

Explanation:

The decay rate of the isotope is modelled after the following first-order linear ordinary differential equation:

\frac{dm}{dt} = -\frac{m}{\tau}

Where:

m - Current isotope mass, measured in kilograms.

t - Time, measured in years.

\tau - Time constant, measured in years.

The solution of this differential equation is:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }

Where m_{o} is the initial mass of the isotope. It is known that radioactive isotope decays at a yearly rate of 0.2 % annually, then, the following relationship is obtained:

\%e = \frac{m(t)-m(t+1)}{m(t)}\times 100\,\% = 0.2\,\%

1 - \frac{m(t+1)}{m(t)} = 0.002

1 - \frac{m_{o}\cdot e^{-\frac{t+1}{\tau} }}{m_{o}\cdot e^{-\frac{t}{\tau} }}=0.002

1 - e^{-\frac{1}{\tau} } = 0.002

e^{-\frac{1}{\tau} } = 0.998

-\frac{1}{\tau} = \ln 0.998

The time constant associated to the decay is:

\tau = -\frac{1}{\ln 0.998}

\tau \approx 499.500\,years

Finally, the half-life of the isotope as a function of time constant is given by the expression described below:

t_{1/2} = \tau \cdot \ln 2

If \tau \approx 499.500\,years, the half-life of the isotope is:

t_{1/2} = (499.500\,years)\cdot \ln 2

t_{1/2}\approx 346.227\,years

The half-life of the radioactive isotope is 346 years.

6 0
3 years ago
Your taking a walk in a warm fall morning the temperature is about 70 degrees Fahrenheit and you cannot see a cloud anywhere in
fomenos

Answer:

The relative humidity is low

Explanation:

The higher the dew point rises, the greater the amount of moisture in the air. The lower the humidity, the lower the dew point. The dew point is low and thus water cannot exist in liquid state but as a gas.

8 0
3 years ago
1. Fluorine-21 has a half-life of approximately 5 seconds. How much of a 200 gram sample would remain after 1 minute.
SSSSS [86.1K]

Answer:

Fluorine-21 has a half-life of approximately 5 seconds. How much of a 200 gram sample would remain after 1 minute.

1/4096

4 0
3 years ago
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