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padilas [110]
1 year ago
7

Taylor works on an art project that uses only rectangular pieces of paper. The first rectangle ha length 3/8 and width of 3in. D

etriment wether the dimensions of each rectangle described as a proportional to the dimensions of tailors first rectangle

Mathematics
1 answer:
chubhunter [2.5K]1 year ago
3 0

By comparing the dimensions above with the dimensions of Taylor's first rectangle, we have the following:

  • No, a length of 6 in, width 3/4 in. is not proportional.
  • Yes, a length of 1/2 in, width 4 in. is not proportional.
  • No, a length of 1 1/8 in, width 9 in. is not proportional.
  • No, a length of 3 in, width 5 5/8 in. is not proportional.

<h3>What is a direct proportion?</h3>

Mathematically, a direct proportion (direct variation) can be represented the following mathematical expression:

y = kx

Where:

  • y and x are the variables or dimensions.
  • k represents the constant of proportionality.

For the dimensions of the rectangular pieces of paper to be proportional, the length and width must remain in a constant ratio.

Next, we would determine the constant of proportionality (k) as follows:

k = y/x

k = (3/8)/3

k = 3/24

k = 1/8

For dimension 1, we have:

k = y/x

k = (6)/(3/4)

k = 24/3

k = 8 (No).

For dimension 2, we have:

k = y/x

k = (1/2)/4

k = 1/2 × 1/4

k = 1/8 (Yes).

For dimension 3, we have:

k = y/x

k = (1 1/8)/9

k = (9/8)/8

k = 9/8 × 1/8

k = 9/64 (No).

For dimension 4, we have:

k = y/x

k = (3)/(5 5/8)

k = 3/(45/8)

k = 3 × 8/45

k = 24/45 (No).

Read more on proportionality here: brainly.com/question/12866878

#SPJ1

Complete Question:

Taylor works on an art project that uses only rectangular pieces of paper. The first rectangle has length 3/8 in. and width 3 in. Determine which dimensions below are proportional to the dimensions of Taylor's first rectangle.

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So, we purchased 9 songs and 4 games for 20.1$.

So, we purchased 10 songs and 6 games for 25.5$.

So, we purchased 10 songs and 10 games for 33.9$.

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First case:

9\cdot 1.29=11.61\\\\4\cdot 2.10=8.4\\\\8.4+11.61=20.01

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Second case:

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So, we purchased 10 songs and 6 games for 25.5$. We have 16 items  for 25.5$.

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a) The object will reach maximum height when its final velocity, v, is 0 m/s.

We apply one of Newton's equations of motion to solve this:

v^2 = u^2 - 2gh

where u = initial velocity = 64 ft/s

g = acceleration due to gravity = 32.2 ft/s

h = height reached by object.

Note: the equation has a negative sign because the object is going upwards, against gravity.

Hence:

0^2 = 64^2 - 2*32.2*h\\\\=> 64.4h = 4096\\\\h = 4096 / 64.4\\\\h = 63.6 ft

The object is now 63.6 ft above the platform (143.6 ft above the ground).

b) Time taken to get to that height can be gotten by using another one of Newton's equations:

v = u - gt

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32.2t = 64\\\\=> t = 64 / 32.2 \\\\t = 1.99 secs

It took the object 1.99 secs to get to that height.

c) When the object begins falling to ground level, it is at a height, h =  143.6 ft and begins moving at initial velocity, u = 0 m/s.

Applying another of Newton's equations of motion, we have that:

h = ut + \frac{1}{2}gt^2

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Therefore, the total time it will take for the object to hit the ground after it is launched will be:

T = time taken to reach maximum height + time taken to hit the floor after it begins descending

T = 1.99 + 2.99

T = 4.98 seconds

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