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nignag [31]
1 year ago
9

A test car carrying a crash test dummy accelerates from 0 to 30 m/s and then crashes into a brick wall. Describe the direction o

f the initial acceleration vector and compare the initial acceleration vector's magnitude with respect to the crash acceleration magnitude.
Question 8 options:

The direction of the initial acceleration vector will point towards the wall, and its magnitude will be less than the acceleration vector of the crash.


The direction of the initial acceleration vector will point away from the wall, and its magnitude will be more than the acceleration vector of the crash.


The direction of the initial acceleration vector will point away from the wall, and its magnitude will be less than the vector of the crash.


The direction of the initial acceleration vector will point towards the wall, and its magnitude will be more than the acceleration vector of the crash.
Physics
1 answer:
serg [7]1 year ago
7 0

The initial acceleration vector will point in the direction of the wall and be less in magnitude than the acceleration vector of the collision, option A is the appropriate reaction.

<h3>What is acceleration?</h3>

The acceleration of the object is the rate at which the item's velocity changes in relation to time.

A test automobile carrying a crash test dummy speeds from 0 to 30 m/s before colliding with a brick wall, as stated in the problem.

The correct response is option A since the initial acceleration vector will point in the direction of the wall and be smaller in magnitude than the acceleration vector of the crash.

To learn more about acceleration, refer to the link;

brainly.com/question/2303856

#SPJ1

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A 42 N net force is applied to a box which slides horizontally across a floor for 9.0
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The Amount of work is done on the box by the net force is 378 Joules.

Explanation:

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A 42 N net force is applied to a box which slides horizontally across a floor.

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Force applied for a displacement of 9.0 m

Displacement = 9.0 m

To Find:

Amount of work is done on the box by the net force = ?

i.e Work = ?

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When a force causes a object to move, work is being done on the object by the force. Work is the measure of energy transfer when a force (F) moves an object through a distance (d).

Formula is given by

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Substituting the given values we get

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8 0
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12. Suppose a person uses a mechanical iack to lift half the weight of a car with a
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Explanation:

a)

Since the jack is 100% efficient, all the input work is converted into output work. So we can write:

W_{in} = W_{out}\\F_{in} d_{in} = F_{out} d_{out}

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F_{in} is the input force applied on the jack

d_{in} is the arm of the input force

F_{out} is the output force applied on the jack

d_{out} is the arm of the output force

Here we have:

F_{out}=\frac{mg}{2}= \frac{(1200 kg)(9.8 m/s^2)}{2}=5880 N is the output force (half the weight of the car)

d_{in} = 40.0 cm = 0.40 m is the arm of the input force

d_{out} = 5.0 mm = 0.005 m is the arm of the output force

Solving for F_{in}, we find the force that must be applied in input to lift the car:

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b)

The efficiency of the jack is given by the ratio between the output work and the input work:

\eta = \frac{W_{out}}{W_{in}}=\frac{F_{out}d_{out}}{F_{in}d_{in}}

where we have:

F_{out}=5880 N is the output force (half the weight of the car)

d_{in} = 40.0 cm = 0.40 m is the arm of the input force

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Here we are told that the input force this time is

F_{in}=90.0N

Substituting into the equation, we find the new efficiency of the jack:

\eta = \frac{(5880)(0.005)}{(90.0)(0.40)}=0.82

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