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ludmilkaskok [199]
3 years ago
8

The expression below was formed by combining different gas laws.

Physics
1 answer:
kap26 [50]3 years ago
7 0

Answer:

Avogadro's law.

Explanation:

Avogadro’s law states that, equal volumes of all gases at the same temperature and pressure contain the same number of molecules.

Mathematically,

V n

V = Kn where V = volume in cm3, dm3, ml or L; n = number of moles of gas;

K = mathematical constant.

The ideal gas equation is a combination of Boyle's law, Charles' law and Avogadro’s law.

V 1/P at constant temperature (Boyle’s law)

V T at constant pressure ( Charles’law)

V n at constant temperature and pressure ( Avogadro’s law )

Combining the equations yields,

V nT/P

Introducing a constant,

V = nRT/P

PV = nRT

Where P = pressure in atm, Pa, torr, mmHg or Nm-2; V = volume in cm3, dm3, ml or L; T = temperature in Kelvin; n = number of moles of gas in mol; R = molar gas constant = 0.082 dm3atmK-1mol-1

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mariarad [96]

Answer:

Moment of inertia of the flywheel, I=1.82\ kg-m^2          

Explanation:

Given that,

The maximum energy stored on  flywheel, E=4\ MJ=4\times 10^6\ J

Angular velocity of the flywheel, \omega=20000\ rev/s=2094.39\ rad/s

We need to find the moment of inertia of the flywheel. The energy of a flywheel in rotational kinematics is given by :

E=\dfrac{1}{2}I\omega^2

I is the moment of inertia of the flywheel

On rearranging we get :

I=\dfrac{2E}{\omega^2}

I=\dfrac{2\times 4\times 10^6}{(2094.39)^2}

I=1.82\ kg-m^2

So, the moment of inertia of the flywheel is I=1.82\ kg-m^2. Hence, this is the required solution.

8 0
3 years ago
Work done can be describe as?​
Neko [114]

Explanation:

In physics, work is the energy transferred to or from an object via the application of force along a displacement. In its simplest form, it is often represented as the product of force and displacement. A force is said to do positive work if (when applied) it has a component in the direction of the displacement of the point of application. A force does negative work if it has a component opposite to the direction of the displacement at the point of application of the force.

Quick Facts: Common symbols, SI unit ...

Work

A baseball pitcher does positive work on the ball by applying a force to it over the distance it moves while in his grip.

Common symbols

W

SI unit

joule (J)

Other units

Foot-pound, Erg

In SI base units

1 kg⋅m2⋅s−2

Derivations from

other quantities

W = F ⋅ s

W = τ θ

Dimension

M L2 T−2

Close

For example, when a ball is held above the ground and then dropped, the work done by the gravitational force on the ball as it falls is equal to the weight of the ball (a force) multiplied by the distance to the ground (a displacement). When the force F is constant and the angle between the force and the displacement s is θ, then the work done is given by:

{\displaystyle W=Fs\cos {\theta }}{\displaystyle W=Fs\cos {\theta }}

Work is a scalar quantity, so it has only magnitude and no direction. Work transfers energy from one place to another, or one form to another. The SI unit of work is the joule (J), the same unit as for energy.

4 0
3 years ago
An object moving with a speed of 5m/s comes to rest in 10s after the brakes are applied . What is the initial velocity​?
Flauer [41]

Initial velocity is 5m/s.

8 0
2 years ago
An ideal monatomic gas at 275 K expands adiabatically and reversibly to six times its volume. What is its final temperature (in
Gwar [14]

The final temperature is 83 K.

<u>Explanation</u>:

For an adiabatic process,

T {V}^{\gamma - 1} = \text{constant}

\cfrac{{T}_{2}}{{T}_{1}} = {\left( \cfrac{{V}_{1}}{{V}_{2}} \right)}^{\gamma - 1}

Given:-

{T}_{1} = 275 \; K  

{T}_{2} = T \left( \text{say} \right)

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{V}_{2} = 6V

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\Rightarrow \cfrac{T}{275} = {\left( \cfrac{1}{6} \right)}^{\frac{2}{3}}  

T  =  275 \times 0.30

T  =  83 K.

3 0
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