Answer: 150 joules
Explanation:
Force applied on a block = 25N
Distance moved by block = 6 m
Workdone = ?
Recall that work is done when force is applied on an object over a distance. And it is measured in joules.
I.e Workdone = Force X Distance
= 25N x 6 metres
= 150 joules
Thus, 150 joules of work is done by the applied force.
Answer:
d) 15.12 N
e) 15.12 N
Explanation:
Draw a free body diagram of the each block.
Block A has three forces on it: weight force mAg pulling down, normal force N pushing up, and tension force T pulling down.
Block B has two forces on it: weight force mBg pulling down, and tension force T pulling up.
Sum of forces on A in the y direction:
∑F = ma
T + N − mAg = mAa
N = mAa + mAg − T
N = mA (a + g) − T
Sum of forces on B in the y direction:
∑F = ma
T − mBg = mBa
T = mBa + mBg
T = mB (a + g)
Plug in values:
T = (1.80 kg) (-1.60 m/s² + 10 m/s²)
T = 15.12 N
N = (3.60 kg) (-1.60 m/s² + 10 m/s²) − 15.12 N
N = 15.12 N
So the answers to (d) and (e) are both 15.12 N.
Answer:
Explanation:
The definition of angular velocity is as follows:
where 
is the angular velocity, and 
is the frequency.
Frequency can also be represented as:
where 
is the period, (the time it takes to conclude a cycle)
with this, the angular velocity is:
The period T of rotation around the sun 365 days, thus, the angular velocity:
if we want the angular velocity in rad/second, we need to convert the 365 days to seconds:
Firt conveting to hous
then to minutes
and finally to seconds
thus, angular velocity in rad/second is:
