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10 months ago

(Can anyone answer this please? I need it ASAP!!) A2B3C4 (in hexadecimal) - 3F2E1D (in hexadecimal) = ______________

Mathematics

1 answer:

netineya [11]10 months ago

7 0

The hexadecimal value from the operation is 6385A7

<h3>Hexadecimal Numbers</h3>

To solve this problem, we have to subtract the hexadecimal numbers from one another.

In doing so, we would subtract 3F2E1D from A2B3C4.

This would give us,

$A2B3C4 - 3F2E1D = 6385A7$

The value of the expression is 6385A7.

Learn more on hexadecimal number here;

brainly.com/question/28450899

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The circumference of the base of a cylinder is 24π mm. A similar cylinder has a base with circumference of 60π mm. The lateral a

earnstyle [38]

Given that the figures are similar polygons, the ratio of their ratios should be equal to the square of the ratio of their circumference. If we let x be the lateral area of the smaller cylinder then,
(x/210π) = (24π/60π)²
The value of x from the equation is,
x = 33.6π
Thus, the area of the smaller cylinder is equal to 33.6π mm².

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2 years ago

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Harlow can bicycle at a rate of 18 miles per hour.How many hours would it take him to bicycle a stretch mark of road that is 450

FromTheMoon [43]

Answer:

8100 Hours

Step-by-step explanation:

We all have heard of miles per hour, so just plug that formula into the question!

Ex. 18 miles PER HOUR x 450 MILES = 8100 hours

Hope this helps!

6 0

2 years ago

How to solve:

natima [27]

Let the first be x and the second be x + 4
x+ x + 4 = 56
2x+4 = 56
2x = 52
∴x= 26

please mark as brainliest

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3 years ago

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I need help with this question

AlexFokin [52]

A
Find the two intersections of the lines. The value of x of the intersections will satisfy the system of equations.
Brainliest pls!

3 0

1 year ago

Solve 2x^2 + x - 4 = 0 <br> X2 +

damaskus [11]

Answer:

$\large \boxed{\sf \ \ x = -\dfrac{\sqrt{33}+1}{4} \ \ or \ \ x = \dfrac{\sqrt{33}-1}{4} \ \ }$

Step-by-step explanation:

Hello, please find below my work.

$2x^2+x-4=0\\\\\text{*** divide by 2 both sides ***}\\\\x^2+\dfrac{1}{2}x-2=0\\\\\text{*** complete the square ***}\\\\x^2+\dfrac{1}{2}x-2=(x+\dfrac{1}{4})^2-\dfrac{1^2}{4^2}-2=0\\\\\text{*** simplify ***}\\\\(x+\dfrac{1}{4})^2-\dfrac{1+16*2}{16}=(x+\dfrac{1}{4})^2-\dfrac{33}{16}=0$

$\text{*** add } \dfrac{33}{16} \text{ to both sides ***}\\\\(x+\dfrac{1}{4})^2=\dfrac{33}{16}\\\\\text{**** take the root ***}\\\\x+\dfrac{1}{4}=\pm \dfrac{\sqrt{33}}{4}\\\\\text{*** subtract } \dfrac{1}{4} \text{ from both sides ***}\\\\x = -\dfrac{1}{4} -\dfrac{\sqrt{33}}{4} \ \ or \ \ x = -\dfrac{1}{4} +\dfrac{\sqrt{33}}{4}$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

4 0

2 years ago