Answer:
see explanation
Step-by-step explanation:
2 chords intersecting inside a circle , then the product of the parts of one chord is equal to the product of the parts of the other chord.
6
BE × ED = AE × CE , that is
10 × 3x = 12(2x + 1) ← distribute parenthesis by 12
30x = 24x + 12 ( subtract 24x from both sides )
6x = 12 ( divide both sides by 6 )
x = 2
then
ED = 3X = 3(2) = 6
7
RJ × JP = SJ × JQ , that is
6 × 3x = 4(4x + 1) ← distribute parenthesis by 4
18x = 16x + 4 ( subtract 16x from both sides )
2x = 4 ( divide both sides by 2 )
x = 2
then
RP = RJ + JP = 6 + 3x = 6 + 3(2) = 6 + 6 = 12
Answer: p=11
Step-by-step explanation:
12p+7)139
-7 -7
12p)132
÷12 ÷12
P)11
That is the distributive property
Answer:
−1 ≤ n + 7 < 9
To solve a compound inequality separate it into two inequalities
That is
n + 7 ≥ - 1 and
n + 7 < 9
Solve the inequality
n + 7 ≥ -1
n ≥ - 8
and
n + 7 < 9
n < 7 - 9
n < 2
Find the intersection
The final answer is
-8 ≤ n < 2
Hope this helps
Answer:
it is 8
Step-by-step explanation:
1+1+1+1+1+1+1+1
2+2+2+2
4+4
8
