Factor out the GCF of
21
b
2
c
2
from
63
b
2
c
4
+
42
b
3
c
2
.
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Factor out the GCF of
21
b
2
c
2
from each term in the polynomial.
Tap for fewer steps...
Factor out the GCF of
21
b
2
c
2
from the expression
63
b
2
c
4
.
21
b
2
c
2
(
3
c
2
)
+
42
b
3
c
2
Factor out the GCF of
21
b
2
c
2
from the expression
42
b
3
c
2
.
21
b
2
c
2
(
3
c
2
)
+
21
b
2
c
2
(
2
b
)
Since all the terms share a common factor of
21
b
2
c
2
, it can be factored out of each term.
21
b
2
c
2
(
3
c
2
+
2
b
)
The greatest common factor
GCF
is the term in front of the factored expression.
21
b
2
c
2
The center of the clock is taken as the origin.The clock is a circle with a diameter 10 units.Radius is half the diameter .Radius = 10 ÷2= 5 units.
The clock is divided in four quadrants .On x axis y=0 and on y axis x=0.
When it is 12 o'clock the hour hand is on positive of y axis.Coordinates of the point at 12 o'clock=(0,5)
When it is 3 o 'clock the hour hand is on positive of x axis .Coordinate of the point at 3o'clock is (5,0)
When it is 6 o'clock the hour hand is on negative of y axis .The coordinates of the point at 6o'clock is (0,-5)
At 9o'clock the hour hand is on negative of x axis .The coordinate of the point at 6o'clock is(-5,0)
Answer:B
I got it right on my test
Step-by-step explanation:
Answer:
i think is 3.3 but i dont know
Step-by-step explanation:
Step-by-step explanation:
Go from the negetive number to 0 to the positive number. -116 to 0 is 116. Then, 0 to 131 is 131. Do 116+131 then you will find your answer.
Hope this helps.
