plz answer for me i will give u brainest if you do.
The confidence interval for the difference p1 - p2 of the population proportion is (0.063, 0.329)
<h3>How to determine the confidence interval?</h3>
The given parameters are:
n₁ = 93; n₂ = 80
p₁ = 0.814; p₂ = 0.618
The critical value at 95% confidence interval is
z = ±1.96
So, we have:
Substitute known values in the above equation
Evaluate
This gives
CI = 0.196 ± 0.133
Expand
CI = (0.196 - 0.133, 0.196 + 0.133)
Evaluate
CI = (0.063, 0.329)
Hence, the confidence interval is (0.063, 0.329)
Read more about confidence interval at:
brainly.com/question/15712887
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X2 is double the amount of x1
I have to do a lot of stuff to do this in the time of time I have to do a lot of work to do this really
We'll use the exponent rule that a^(b+c) = a^b*a^c
to break up 17^16 into 17^(14+2) = 17^14*17^2
That allows us to factor like so
17^16+17^14
17^14*17^2+17^14*1
17^14(17^2 + 1)
Computing 17^14 is a lot more difficult compared to computing 17^2 + 1, assuming you only could use paper and pencil.
Note that 17^2 = 17*17 = 289, so 17^2 + 1 = 289+1 = 290
Because 290 ends in a 0, this means that 5 is a factor
290 = 5*58
This makes 5 to be a factor of the original expression.
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So overall,
17^16+17^14 = 17^14(17^2 + 1) = 17^14*290 = 17^14*5*58 = 5*17^14*58
The stuff "17^14*58" doesn't matter. All we care about is that factor of 5.
Since 5 is a factor, this means that 17^16+17^14 is a multiple of 5, or 17^16+17^14 is divisible by 5.
Phrased another way, 17^16+17^14 all divided over 5 leads to some integer. In this case, the integer would be the result of 17^14*58.
