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Igoryamba
1 year ago
11

use the graphing calculator to graph the quadratic function y = x2 − 5x − 36. Which value is a solution of 0 = x2 − 5x − 36?

Mathematics
1 answer:
daser333 [38]1 year ago
3 0

The solutions of the quadratic equation x² - 5x - 36 = 0 are -4 and 9.

The graph is attached below.

  • We are given a quadratic function.
  • A polynomial equation of degree two in one variable is a quadratic equation.
  • The function given to us is :
  • y = x² - 5x - 36
  • We need to find the solution of the quadratic function.
  • To find the roots, let y = 0.
  • x² - 5x - 36 = 0
  • Use the quadratic formula.
  • In elementary algebra, the quadratic formula is a formula that gives the solution(s) to a quadratic equation.
  • x = [-b±√b²-4ac]/2a
  • x = [-(-5) ± √25 - 4(1)(-36)]/2(1)
  • x = (5 ± √25 + 144)/2
  • x = (5 ± √169)/2
  • x = (5 ± 13)/2
  • x = 9 or x = -4

To learn more about functions, visit :

brainly.com/question/12431044

#SPJ1

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I REALLY NEED HELP
Ede4ka [16]
There are 60 minutes in one hour, thus, 45 miles per hour is 45 miles per 60 minutes, thus

\bf \begin{array}{ccll}
miles&minutes\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
45&60\\
240&m
\end{array}\implies \cfrac{45}{240}=\cfrac{60}{m}\implies m=\cfrac{240\cdot 60}{45}
8 0
3 years ago
This high school stadium contains a track that surrounds a soccer field. The soccer field is 100 yards long and 70 yards
liberstina [14]

Answer:

Given : The high school stadium contains a track that surrounds a soccer field. The soccer field is 100 yards long and 70 yards wide.

The school decided to cover the semicircles with grass to create a space for stretching and other activities.

To Find: area of one of the semicircles at either end of the track

How many square yards of grass will the school need to cover the entire circle?

Solution:

Diameter of semicircle = 70 yards

Radius of semicircle = 70/2 = 35 yards

Area of semicircle at one end = (1/2)πr²

= (1/2)(22/7)35²

= 1,925 sq yards

area of one of the semicircles at either end of the track = 1,925 sq yards

square yards of grass will the school need to cover the entire circle

= 2 x   1,925

= 3850 sq yards

distance around one of the semicircles at either end of the soccer field = πr  = (22/7) 35 = 110 yards

distance around the inner lane of the track  = 100 + 100 + 110 + 110

= 420 yards

Please Mark as Brainliest

Hope this Helps

4 0
3 years ago
PLEASE HELP ITS URGENT
Sveta_85 [38]
X^2-22x-48=0
x^2-24x+2x-48=0
x(x-24)+2(x-24)
(x+2)(x-24)

Solve by grouping if you are able to find distinct factors that multiply to the last term and add to the middle term...this method is rather easy with easy to manage numbers. Complete the square if you cannot find distinct factors that multiply to the last term and add to the middle term. Completing the square helps when the equation is in the form of a parabola.
6 0
4 years ago
If cos 37 degrees is close to 4/5, which is closest to the measure of line OP?
geniusboy [140]
 We know that ON = 80 cm and ∠ O = 37°.
cos 37° = 4/5
Adjacent / Hypotenuse = cos∠O
80/OP = cos 37°
80/ OP = 4/5
OP = 80 : 4/5 = 80 · 5/4 = 100
Answer:
d. 100 cm.
3 0
3 years ago
Read 2 more answers
John bought 2 sodas for $0.80 each. The model shows this situation. Which equation shows how to find the total cost, in dollars
Genrish500 [490]

Answer:

A) 2 x 0.80= 1.60

Step-by-step explanation:

get 80 on the cents and times it by how many soda's you got (2) then times it by normal which will get you 16 so add a zero at the end to make the answer.

7 0
3 years ago
Read 2 more answers
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