There are 60 minutes in one hour, thus, 45 miles per hour is 45 miles per 60 minutes, thus
Answer:
Given : The high school stadium contains a track that surrounds a soccer field. The soccer field is 100 yards long and 70 yards wide.
The school decided to cover the semicircles with grass to create a space for stretching and other activities.
To Find: area of one of the semicircles at either end of the track
How many square yards of grass will the school need to cover the entire circle?
Solution:
Diameter of semicircle = 70 yards
Radius of semicircle = 70/2 = 35 yards
Area of semicircle at one end = (1/2)πr²
= (1/2)(22/7)35²
= 1,925 sq yards
area of one of the semicircles at either end of the track = 1,925 sq yards
square yards of grass will the school need to cover the entire circle
= 2 x 1,925
= 3850 sq yards
distance around one of the semicircles at either end of the soccer field = πr = (22/7) 35 = 110 yards
distance around the inner lane of the track = 100 + 100 + 110 + 110
= 420 yards
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X^2-22x-48=0
x^2-24x+2x-48=0
x(x-24)+2(x-24)
(x+2)(x-24)
Solve by grouping if you are able to find distinct factors that multiply to the last term and add to the middle term...this method is rather easy with easy to manage numbers. Complete the square if you cannot find distinct factors that multiply to the last term and add to the middle term. Completing the square helps when the equation is in the form of a parabola.
We know that ON = 80 cm and ∠ O = 37°.
cos 37° = 4/5
Adjacent / Hypotenuse = cos∠O
80/OP = cos 37°
80/ OP = 4/5
OP = 80 : 4/5 = 80 · 5/4 = 100
Answer:
d. 100 cm.
Answer:
A) 2 x 0.80= 1.60
Step-by-step explanation:
get 80 on the cents and times it by how many soda's you got (2) then times it by normal which will get you 16 so add a zero at the end to make the answer.