Answer;
C) The second arc should be centered at C.
Explanation;
Assuming the goal is to construct a line parallel to AB that passes through given point C.
-Draw a line through C and across AB at an angle creating D.
- With the compass width about half of DC, and center D, draw the first arc to cross both lines.
-Using the same compass width , draw the second arc with center C.
-Then set the compass width to the lower arc (the first arc)
- Move the compass to the second arc. Mark off an arc to make point E
-Draw a straight line through C and E
Thus the line CE will be parallel to line AB
Answer:
(a)9×3=37' 97 and 8 are factors of 37
Answer:
-6
Step-by-step explanation:
Consider the triangles formed by the lines of sight in parts a and b. In part a, the distance from the horizontal to the base of the antenna is 82.0*tan31.0º; in part b, the distance from the horizontal to the top is 82.0*tan34.2º. The antenna height is the difference between these
<span>h = 82.0*tan34.2º - 82.0*tan31.0º = 82.0*(tan34.2º - tan31.0º) = 6.46 m</span>
Answer:
A
Step-by-step explanation:
I remember it by:
acute: a cute little angle that is smaller than 90 degrees