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leonid [27]
3 years ago
5

Kenyon arrange flowers in a identical bouquets if he had 21 red flowers and 28 yellow flowers what is the greatest number of bou

quets he could make
Mathematics
1 answer:
Contact [7]3 years ago
5 0
84 is the number I came up with.
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The amount of soda a dispensing machine pours into a 12-ounce can of soda follows a normal distribution with a mean of 12.30 oun
Ugo [173]

Answer: A) .1587

Step-by-step explanation:

Given : The amount of soda a dispensing machine pours into a 12-ounce can of soda follows a normal distribution with a mean of 12.30 ounces and a standard deviation of 0.20 ounce.

i.e. \mu=12.30 and \sigma=0.20

Let x denotes the amount of soda in any can.

Every can that has more than 12.50 ounces of soda poured into it must go through a special cleaning process before it can be sold.

Then, the probability that a randomly selected can will need to go through the mentioned process =  probability that a randomly selected can has more than 12.50 ounces of soda poured into it =

P(x>12.50)=1-P(x\leq12.50)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{12.50-12.30}{0.20})\\\\=1-P(z\leq1)\ \ [\because z=\dfrac{x-\mu}{\sigma}]\\\\=1-0.8413\ \ \ [\text{By z-table}]\\\\=0.1587

Hence, the required probability= A) 0.1587

6 0
2 years ago
Let r= .12 be the reserve rate. What is the money multiplier?
ZanzabumX [31]
The money multiplier is 1/ 0.12 
5 0
3 years ago
Read 2 more answers
What does this equal?
Ludmilka [50]
Use the photo Math calculator the answer would be on their
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3 years ago
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If k is non zero digit for which base of k is the sum, 1+kk=100 true?
Anna007 [38]
No, i don't think it's true
4 0
3 years ago
??????????????????????????????
Anna007 [38]

You want to find the time <em>t</em> such that

\$1000 = \$200 e^{0.04t}

Divide both sides by $200 :

\dfrac{\$1000}{\$200} = 5 = e^{0.04t}

Take the logarithm of both sides:

\ln(5) = \ln(e^{0.04t}) = 0.04t\ln(e) = 0.04t

Divide both sides by 0.04 and solve for <em>t</em> :

t = \dfrac{\ln(5)}{0.04} \approx 40.24 \approx \boxed{40}

6 0
3 years ago
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