Answer:
Step-by-step explanation:
Given the formula for calculating the distance travelled expressed as;
s=1/2at^2
Given
a = 3
t = 10
Required
lower bound of s
Substitute the given values into the equation;
s=1/2at^2
S = 1/2(3)(10)^2
S = 1/2 * 3 * 100
S = 3 * 50
S = 150
Hence the lower bound of distance S is 150
I am setting the week hourly rate to x, and the weekend to y. Here is how the equation is set up:
13x + 14y = $250.90
15x + 8y = $204.70
This is a system of equations, and we can solve it by multiplying the top equation by 4, and the bottom equation by -7. Now it equals:
52x + 56y = $1003.60
-105x - 56y = -$1432.90
Now we add these two equations together to get:
-53x = -$429.30 --> 53x = $429.30 --> (divide both sides by 53) x = 8.10. This is how much she makes per hour on a week day.
Now we can plug in our answer for x to find y. I am going to use the first equation, but you could use either.
$105.30 + 14y = $250.90. Subtract $105.30 from both sides --> 14y = $145.60 divide by 14 --> y = $10.40
Now we know that she makes $8.10 per hour on the week days, and $10.40 per hour on the weekends. Subtracting 8.1 from 10.4, we figure out that she makes $2.30 more per hour on the weekends than week days.
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Answer:
Step-by-step explanation:
Part A
This is a combination problem. Order does not matter.
36C6
36!/(30! 6!)
36 * 35 * 34 * 33 * 32 * 31/ 6!
1402410240/6!
1947792
Part B
1 / (36C6)
0.000000513 or
0.0000005
You didn’t finish asking the question. So I will say they work differently at different paces.