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alisha [4.7K]
1 year ago
5

What is an example of a situation that you might be able to use an equation with a single unknown to help understand? What is an

example of a situation that you might not be able to use an equation with a single unknown to understand? What makes an equation with a single unknown helpful in one of your examples but not the other? What patterns exist in your two examples that might be helpful in determining when to use a simple equation?
Mathematics
1 answer:
nalin [4]1 year ago
5 0

Suppose we want to know the total cost of buying x toys and we know that each toy costs $2. The relationship between the cost and the number of toys is

C(x) = 2x

If we purchase 6 toys, the cost would be

C(6) = 2*6 = $12

This is an example where it's adequate to use a single variable (or unknown) to find the value of another variable.

Now suppose we want to know the total cost of buying x toys for $2 each and include the tax rate in the calculations.

If we know the tax rate r, we can compute the total cost as

C(X,r) = 2x*(1 + r/100)

For example, to purchase x=6 toys and the tax rate is r=8%, the total cost is:

C(6,8) = 2*6*(1 + 8/100)=$12.96

If we had tried to calculate this cost without the use of two unknowns, it would have not been possible.

Thus, the pattern to use one or two variables depends on how many factors determine the final result.

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Work out the value of angle x and how ??
frutty [35]

Answer:

160 degrees

Step-by-step explanation:

Step 1: A straight line is 180 degrees. So 180 - 100, is 80 degrees. as the opposite angle measurement of the 100 degree.

Step 2: An isosceles triangle has two equal angle measurements, so two of its angles are 80 degrees.

Step 3: All angles in a triangle equal 180 degrees. So add them up (we will call the missing angle, Z)     180 = 80+80+Z.      which equals 180= 160+z

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6 0
3 years ago
Yochanan walked from home to the bus stop at an average speed of 5 km / h. He immediately got on his school bus and traveled at
kari74 [83]

Answer: 5 km walking and 30 km by bus

Step-by-step explanation:

Yochanan walked from home to the bus stop at an average speed of 5 km / h. He immediately got on his school bus and traveled at an average speed of 60 km / h until he got to school. The total distance from his home to school is 35 km, and the entire trip took 1.5 hours. How many km did Yochanan cover by walking and how many did he cover by travelling on the bus?

walking - 5km/h                                         bus - 60km/h

distance walking - d₁                                 distance bus - d₂

time walking - t₁                                         time bus - t₂

d₁ + d₂ = 35

t₁ + t₂ = 1.5

v = d/t

vwalking = d₁/t₁

5 = d₁/t₁ ⇒ d₁ = 5t₁

vbus = d₂/t₂

60 = d₂/t₂ ⇒ d₂ = 60t₂

d₁ + d₂ = 35 ⇒ 5t₁ + 60t₂ = 35

_________________________

5t₁ + 60t₂ = 35

t₁ + t₂ = 1.5  (*-5)

5t₁ + 60t₂ = 35

-5t₁ -5t₂ = -7.5   (+)

__________________________

55t₂ = 27.5

t₂ = 27.5/55 = 0.5 h

t₁ + t₂ = 1.5 ⇒ t₁ = 1.5 - 0.5 = 1h

d₁ = 5t₁ ⇒ d₁ = 5.1 = 5 km

d₂ = 60t₂ ⇒ d₂ = 30.0.5 = 30 km

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Two angles are complementary if the sum of their measures is 90°. Find two complementary angles such that one of the angles is 1
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Bro that's a lot, i don't know what the heck you are talking about.
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