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alisha [4.7K]
1 year ago
5

What is an example of a situation that you might be able to use an equation with a single unknown to help understand? What is an

example of a situation that you might not be able to use an equation with a single unknown to understand? What makes an equation with a single unknown helpful in one of your examples but not the other? What patterns exist in your two examples that might be helpful in determining when to use a simple equation?
Mathematics
1 answer:
nalin [4]1 year ago
5 0

Suppose we want to know the total cost of buying x toys and we know that each toy costs $2. The relationship between the cost and the number of toys is

C(x) = 2x

If we purchase 6 toys, the cost would be

C(6) = 2*6 = $12

This is an example where it's adequate to use a single variable (or unknown) to find the value of another variable.

Now suppose we want to know the total cost of buying x toys for $2 each and include the tax rate in the calculations.

If we know the tax rate r, we can compute the total cost as

C(X,r) = 2x*(1 + r/100)

For example, to purchase x=6 toys and the tax rate is r=8%, the total cost is:

C(6,8) = 2*6*(1 + 8/100)=$12.96

If we had tried to calculate this cost without the use of two unknowns, it would have not been possible.

Thus, the pattern to use one or two variables depends on how many factors determine the final result.

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Select the correct answer.
Kaylis [27]

For this case we have that by definition, the volume of a rectangular prism is given by:

V = A_ {b} * h

Where:

A_ {b}:It is the area of the base of the prism

h: It is the height

A_ {b} = w * l

Where:

w: is the width

l: is the length

According to the data of the statement we have:

w = 16 \ in\\l = 4h\\V = 4,096 \ in ^ 3

Substituting the data we have:

A_ {b} = 16 * 4h = 64h\\64h * h = 4,096\\64h ^ 2 = 4,096\\h ^ 2 = \frac {4096} {64}\\h ^ 2 = 64\\h = \pm \sqrt {64}\\

We choose the positive value: h = 8

So the height is8 \ in

Answer:

8 \ in

6 0
3 years ago
Plz help i need it!!!!!!!
Flauer [41]

Answer:

b

Step-by-step explanation:

please answer my last question on my profile for 23 points

8 0
3 years ago
Find the surface area of each figure.
timurjin [86]

Answer:

For a cylinder of radius R and height H, the surface area is given by:

A = 4*pi*R^2 + H*(2*pi*R)

Where pi = 3.14

We can just use that formula for each one of the given cylinders.

1) We can see that the diameter is 10 yd, and the radius is half of the diameter, then the radius is:

R = 10yd/2 = 5yd

And the height is 3yd, then H = 3yd

Replacing these in the area equation, we get:

A = 4*3.14*(5 yd)^2 + 3yd*(2*3.14*5yd) = 408.2 yd^2

2) Here we can see that the diameter is 24 cm, then the radius is:

R = 24cm/2 = 12cm

And the height is H = 10cm

Then the area is:

A = 4*3.14*(12 cm)^2 + 10cm*(2*3.14*12cm) = 2,562.24 cm^2

3) In this case we have a radius equal to 12 cm, and a height equal to 7 cm, then the area is:

A = 4*3.14*(12 cm)^2 + 7cm*(2*3.14*12cm) = 2,336.16cm^2

4) Here is hard to see the measures, I think that here we have:

diameter = 8m

Then R = 8m/2 = 4m

And the height is also 8m, H = 8m

Then the area is:

A = 4*3.14*(4 m)^2 + 8 m*(2*3.14*4m) =401.92 m^2

6 0
3 years ago
Cheri paid $6.50 for the bunch of grapes with the weight of 2.5 pounds. What is the price per pound?
kotegsom [21]
It would be $2.6 (or $2.60) per pound.
3 0
3 years ago
Solve the following quadratic equation 6x^2-5x-4=0
jeka94

Answer:

=

−

±

2

−

4

√

2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}

x=2a−b±b2−4ac​​

Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.

6

2

−

5

−

4

=

0

6x^{2}-5x-4=0

6x2−5x−4=0

=

6

a={\color{#c92786}{6}}

a=6

=

−

5

b={\color{#e8710a}{-5}}

b=−5

=

−

4

c={\color{#129eaf}{-4}}

c=−4

=

−

(

−

5

)

±

(

−

5

)

2

−

4

⋅

6

(

−

4

)

√

2

⋅

6

Step-by-step explanation:

6 0
3 years ago
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