Answer:
Step-by-step explanation:
Assuming that all of the 255 sold seats were filled, then
[tex]\frac{sold}{total} *100\\[percent filled]
(225/260)*100=86.53%
100%-86.53%=13.4%
13.4% of seats are empty!
Answer:
b) 0.2961
c) 0.2251
d) Mean = 11.25, Standard deviation = 1.667
Step-by-step explanation:
We are given the following information:
We treat trucks undergoing a brake inspection passin as a success.
P( trucks undergoing a brake inspection passes the test) = 75% = 0.75
a) Conditions for binomial probability distribution
- There are n independent trial.
- Each trial have a success probability p
- The probability of success is same for all trials.
Then the number of trucks undergoing a brake inspection follows a binomial distribution, where
where n is the total number of observations, x is the number of success, p is the probability of success.
Now, we are given n = 15
b) P(proportion of groups will between 8 and 10 trucks pass the inspection)
We have to evaluate:
c) P( exactly 3 trucks fail the inspection)
p = 0.25
d) Mean and standard deviation

Answer:
μ ≈ 2.33
σ ≈ 1.25
Step-by-step explanation:
Each person has equal probability of ⅓.
![\left[\begin{array}{cc}X&P(X)\\1&\frac{1}{3}\\2&\frac{1}{3}\\4&\frac{1}{3}\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7DX%26P%28X%29%5C%5C1%26%5Cfrac%7B1%7D%7B3%7D%5C%5C2%26%5Cfrac%7B1%7D%7B3%7D%5C%5C4%26%5Cfrac%7B1%7D%7B3%7D%5Cend%7Barray%7D%5Cright%5D)
The mean is the expected value:
μ = E(X) = ∑ X P(X)
μ = (1) (⅓) + (2) (⅓) + (4) (⅓)
μ = ⁷/₃
The standard deviation is:
σ² = ∑ (X−μ)² P(X)
σ² = (1 − ⁷/₃)² (⅓) + (2 − ⁷/₃)² (⅓) + (4 − ⁷/₃)² (⅓)
σ² = ¹⁴/₉
σ ≈ 1.25
Answer:
Choice 4.
Step-by-step explanation:
f(g(x))
Replace g(x) with x^2+8 since g(x)=x^2+8.
f(g(x))
f(x^2+8)
Replace old input,x, in f with new input, (x^2+8).
f(g(x))
f(x^2+8)
2(x^2+8)+5
Distribute:
f(g(x))
f(x^2+8)
2(x^2+8)+5
2x^2+16+5
Combine like terms:
f(g(x))
f(x^2+8)
2(x^2+8)+5
2x^2+16+5
2x^2+21
6% is less than 48%. Due to the reason that 48% is a larger portion.