Question

According to Boyle's law, PV = k, what was the pressure to the nearest tenth at the time of the firstmeasurement given the following information?Vi = 7,450 mLP2 = 8.25 atmV2 = 1,645 mLA. 37.4 atmB. 4.52 atm

Answer 1

Solution

Given data

According to Boyle's law, PV = K

The required general equation thus is

$\begin{gathered} p_1v_1=p_2v_2 \\ p_1=? \\ p_2=\text{ 8.25 atm} \\ v_2=1,645ml \\ v_1=7450ml \end{gathered}$

Substituting these values we find that the initial pressure is

$\begin{gathered} p_1\times7450\text{ = 8.25 }\times1645 \\ p_1=\frac{13571.25}{7450} \\ p_1=1.82164\text{atm} \\ p_1\approx1.8atm \end{gathered}$

The initial pressure to the nearest tenth, therefore, is 1.8 atm.

The final answer, therefore, is Option D