Answer: About
Step-by-step explanation:
The missing figure is attached.
Notice in the first picture that Alberta has a complex shape.
You can calculate the area of a complex shape by decomposing it into polygons whose areas can be calculated easily.
Observe the second picture. Notice that it can be descompose into two polygons: A trapezoid and a rectangle.
The area of the trapezoid can be calcualted with the formula:

Where "h" is the height, "B" is the long base and "b" is short base.
And the area of the rectangle can be found with the formula:

Wkere "l" is the lenght and "w" is the width.
Then, the apprximate area of Alberta is:

Substituting vallues, you get:

Therefore, the area of of Alberta is about
.
The vector function is, r(t) = 
Given two surfaces for which the vector function corresponding to the intersection of the two need to be found.
First surface is the paraboloid, 
Second equation is of the parabolic cylinder, 
Now to find the intersection of these surfaces, we change these equations into its parametrical representations.
Let x = t
Then, from the equation of parabolic cylinder,
.
Now substituting x and y into the equation of the paraboloid, we get,

Now the vector function, r(t) = <x, y, z>
So r(t) = 
Learn more about vector functions at brainly.com/question/28479805
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I think it’s 3
i multiplied .2222 times 18
Answer:
x=9
Step-by-step explanation:
We have two similar triangles because both lines are parallel, use proportions to solve:

ANSWER

EXPLANATION
The given fractions are:

We factor to obtain:

We cancel the common factors to get:

We multiply the numerators and also multiply the denominators to get:

Therefore the two fractions simplifies to 