The massless spring of a spring gun has a force constant
1 answer:
The initial compression of the spring is determined as 0.54 m.
<h3>What is the compression of the spring?</h3>
The compression of the spring is determined by applying the principle of conservation of linear momentum as follows;
E = U
mgh = ¹/₂kx²
2mgh = kx²
x² = 2mgh/k
x = √(2mgh/k)
where;
- m is the mass of the projetcile
- h is the height
- k is the spring constant = 0.07 N/cm = 7 N/m
- x is the compression of the spring
x = √(2 x 0.021 x 9.8 x 5)/7)
x = 0.54 m
Learn more about compression of spring here: brainly.com/question/2114706
#SPJ1
You might be interested in
Answer:
objects with greater mass should have greater inertia
The answer is c for that question
Answer:
Length (l) = 6 m
height (h) = 3 m
Load(L) = 500 N
Effort (E) = ?
we know the principal that
E * l = L * h
6 E = 500 * 3
6E = 1500
E = 250
therefore 250 N work is done on the barrel.
A higher frequency. I just got this answer on usa test prep.
