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romanna [79]
3 years ago
8

A student was trying to find the relationship between mass and force. He placed four different masses on a table and pulled them

using a spring scale. The table shows the different masses used in the experiment and the force required to pull each mass. The student concluded that more force was required to pull heavier objects. What comment would you make regarding his conclusion? A) No clear relation can be observed between mass and force from the data. B) There is a direct proportion between the mass and force listed in the table. C) Gravity should have been taken into account while performing the experiment. D) There is an inverse proportion between the mass and force listed in the table.
Mass (kg) Force (N)

5 25

10 50

15 75

20 100
Physics
2 answers:
Gwar [14]3 years ago
5 0

Answer:

B. There is a direct proportion between the mass and force listed in the table.

Explanation:

From the table, the values of force increases with increase in the value of mass.

if 5kg=25 N

Finding the contant of proportionality k;

k=25/5=5

thus M=k(F)...........where M is mass in kg and F is force in newton, then

M=5F

This show that for every value of mass, we get the value of Force if we multiply by a contant k=5

This means there is a direct proportionality relation between mass and force in the table.

saul85 [17]3 years ago
4 0

Answer: Correct answer is B.

Hope this helps.

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A wire that is 0.65 m long and carrying a current of 8.2 A is at right angles to a uniform magnetic field. The force on the wire
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Answer:

0.075 T

Explanation:

When a current-carrying wire is immersed in a region with magnetic field, the wire experiences a force, given by

F=ILB sin \theta

where

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\theta is the angle between the direction of I and B

In this problem we have:

L = 0.65 m is the length of the wire

I = 8.2 A is the current in the wire

F = 0.40 N is the force experienced by the wire

\theta=90^{\circ} since the current is at right angle with the magnetic field

Solving the formula for B, we find the strength of the magnetic field:

B=\frac{F}{IL sin \theta}=\frac{0.40}{(8.2)(0.65)(sin 90^{\circ})}=0.075 T

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Explanation:

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PLEASE HELP!!! <br><br> i’ll mark brainliest if you’re correct
dedylja [7]

\qquad \qquad\huge \underline{\boxed{\sf Answer}}

The net force acting on the block is ~

\qquad \sf  \dashrightarrow \: 10 + 5

\qquad \sf  \dashrightarrow \: 15 \:N

So, the Answer in the boxes will be ~

\boxed{ \sf15} \:  \boxed{ \sf N}

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