As we know that fulcrum is shifted to one side by 1.33 cm
so here let say left side mass is m1 while on other side mass is m2
so we will have
now in order to find the percentage we have
so it is 10.5 % less mass
Wait a sec.. what is a diode? i would help if i knew what that was, sorry lol
Answer:
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Explanation:
We have to add two vectors.
Vector #1: 0.15 m/s north
Vector #2: 1.50 m/s east
Their sum:
Magnitude: √(0.15² + 1.50²)
Magnitude = √(0.0225+2.25)
Magnitude = √2.2725
Magnitude = <em>1.5075 m/s</em>
Direction = arctan(0.15/1.50) north of east
Direction = <em>5.71° north of east</em>
<h2>The acceleration of car is 0.2 ms⁻²</h2>
Explanation:
When the car moves , the distance covered is calculated by the relation
S = u t + a t²
In this question u = 0 , because car was at rest initially
Thus S = a t²
here S is displacement and a is the acceleration of car
Therefore 360 = a ( 60 )²
Because time taken is one minute or 60 seconds
Therefore a =
or a = 0.2 m s⁻²