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stepladder [879]
3 years ago
5

A(n) ___ object is not electrically neutral.

Physics
1 answer:
Korvikt [17]3 years ago
8 0

Answer:

No, there are always protons, neutrons, and electrons. When an object is neutral, it means the positive and negative charges sum to zero (are equal and opposite). NO, if an object has no net charge it simply means that the amount of positive and negative charges (protons and neutrons) are the same.

Explanation:

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At 900.0 K, the equilibrium constant (Kp) for the following reaction is 0.345. 2SO2(g)+O2(g)→2SO3(g) At equilibrium, the partial
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Answer : The partial pressure of SO_3 is, 67.009 atm

Solution :  Given,

Partial pressure of SO_2 at equilibrium = 30.6 atm

Partial pressure of O_2 at equilibrium = 13.9 atm

Equilibrium constant = K_p=0.345

The given balanced equilibrium reaction is,

2SO_2(g)+O_2(g)\rightleftharpoons 2SO_3(g)

The expression of K_p will be,

K_p=\frac{(p_{SO_3})^2}{(p_{SO_2})^2\times (p_{O_2})}

Now put all the values of partial pressure, we get

0.345=\frac{(p_{SO_3})^2}{(30.6)^2\times (13.9)}

p_{SO_3}=67.009atm

Therefore, the partial pressure of SO_3 is, 67.009 atm

6 0
3 years ago
During a race, four competitors of the same weight rode identical bicycles for 10 minutes. At 8 minutes, which bicycle was movin
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Answer:

All the competitors will move with the same velocity.

Explanation:

Here, the situations for each competitor are identical. Thus, they will exert the same force and hence, their velocities at each instants will be identical.

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3 years ago
The larger the push, the larger the change in velocity. This is an example of Newton's Second Law of Motion which states that th
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According to Newton, an object will only accelerate if there is a net or unbalanced forceacting upon it. The presence of an unbalanced force will accelerate an object - changing its speed, its direction, or both its speed and direction.
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Read 2 more answers
Vitamins and iron are nutrients that provide energy to the human body.<br> A true<br> B false
SIZIF [17.4K]
I think it is A. but then you can also produce your own energy
4 0
2 years ago
Assume that the position vector of A is r=i+j+k . Determine the moment about the origin O if the force F=(1)i+(0)j+(5)k . The mo
ddd [48]

Answer:

M₀ = 5i - 4j - k

Explanation:

Using the cross product method, the moment vector(M₀) of a force (F) is about a given point is equal to cross product of the vector A from the point (r) to anywhere on the line of action of the force itself. i.e

M₀ = r x F

From the question,

r = i + j + k

F = 1i + 0j +  5k

Therefore,

M₀ = (i + j + k) x (1i + 0j +  5k)

M₀ = \left[\begin{array}{ccc}i&j&k\\1&1&1\\1&0&5\end{array}\right]

M₀ = i(5 - 0) -j(5 - 1) + k(0 - 1)

M₀ = i(5) - j(4) + k(-1)

M₀ = 5i - 4j - k

Therefore, the moment about the origin O of the force F is

M₀ = 5i - 4j - k

3 0
2 years ago
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