Complete Question:
A purse at radius 2.00 m and a wallet at radius 3.00 m travel in uniform circular motion on the floor of a merry-go-round as the ride turns.
They are on the same radial line. At one instant, the acceleration of the purse is (2.00 m/s2 ) i + (4.00 m/s2 ) j .At that instant and in unit-vector notation, what is the acceleration of the wallet
Answer:
aw = 3 i + 6 j m/s2
Explanation:
- Since both objects travel in uniform circular motion, the only acceleration that they suffer is the centripetal one, that keeps them rotating.
- It can be showed that the centripetal acceleration is directly proportional to the square of the angular velocity, as follows:

- Since both objects are located on the same radial line, and they travel in uniform circular motion, by definition of angular velocity, both have the same angular velocity ω.
∴ ωp = ωw (2)
⇒ 

- Dividing (4) by (3), from (2), we have:


Answer:
12.17 m/s²
Explanation:
The formula of period of a simple pendulum is given as,
T = 2π√(L/g)........................ Equation 1
Where T = period of the simple pendulum, L = length of the simple pendulum, g = acceleration due to gravity of the planet. π = pie
making g the subject of the equation,
g = 4π²L/T²................... Equation 2
Given: T = 1.8 s, l = 1.00 m
Constant: π = 3.14
Substitute into equation 2
g = (4×3.14²×1)/1.8²
g = 12.17 m/s²
Hence the acceleration due to gravity of the planet = 12.17 m/s²
Answer:
2.2N
Explanation:
Given parameters:
Work done = 379.5J
Height = 173m
Unknown:
Amount of force exerted on the sled = ?
Solution:
The amount of force she exerted on the sled is the same as her weight.
Work done is the force applied to move a body through a distance.
Work done = mgh
m is the mass
g is the acceleration due to gravity
h is the height
mg = weight;
Work done = weight x h
379.5 = weight x 173
weight =
= 2.2N
The mass is still 10 kg. But instead of weighing 98N as it does on Earth, it weighs 245N on Jupiter.