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juin [17]
3 years ago
14

A circle with a radius of 15.4 meters. Which statements are true about the circle shown? Check all that apply. The diameter of t

he circle is 30.8 m. The circumference in terms of Pi is 30.8Pi m. The circumference of the circle can be found using 2(Pi)(15.4) The approximate circumference of the circle rounded to the nearest tenth is 96.7 m. A little more than 6 diameters could be wrapped around the circle.
Mathematics
1 answer:
Dafna1 [17]3 years ago
5 0

Step-by-step explanation:

the diameter of a circle is simply 2×radius.

2×15.4 = 30.8 m

the diameter is 30.8 m is true.

the circumference of a circle is

2×pi×radius

2×pi×15.4 = 30.8×pi m

the circumference is 30.8pi m is true.

therefore, the circumference can be found using

2(pi)(15.4)

is true.

now, doing the pi multiplication :

30.8 × pi = 96.76105373... m

the approximate circumference is 96.7 m is true.

6 diameters would be

30.8×6 = 184.8 m

that is much longer than the circumference.

so, more than 6 diameters could be wrapped around the circle is false, if we understand it that this is supposed to wrap the circle once without any overhanging remainder.

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2 years ago
Patrick has just finished building a pen for his new dog. The pen is 3 feet wider than it is long. He also built a doghouse to p
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General Idea:

(i) Assign variable for the unknown that we need to find

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Applying the concept:

Given: x represents the length of the pen and y represents the area of the doghouse

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Length \; of\; the \; pen = x\\ Width \; of\; the\; pen=x+3

------

<u>Statement 2: "He also built a doghouse to put in the pen which has a perimeter that is equal to the area of its base"</u>

Area \; of\; the\; Dog \; house=y\\ Perimeter \; of\; Dog\; house=y

------

<u>Statement 3: "After putting the doghouse in the pen, he calculates that the dog will have 178 square feet of space to run around inside the pen."</u>

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<u>Statement 4: "The perimeter of the pen is 3 times greater than the perimeter of the doghouse."</u>

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The systems of equations that can be used to determine the length and width of the pen and the area of the doghouse is given in Option B.

178=x^2+3x-y\\ \\ -6=4x-3y

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