Answer:
x = √39
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Trigonometry</u>
- [Right Triangles Only] Pythagorean Theorem: a² + b² = c²
Step-by-step explanation:
<u>Step 1: Identify</u>
Leg <em>a</em> = <em>x</em>
Leg <em>b</em> = 5
Hypotenuse <em>c</em> = 8
<u>Step 2: Solve for </u><em><u>x</u></em>
- Substitute [PT]: x² + 5² = 8²
- Isolate <em>x</em> term: x² = 8² - 5²
- Exponents: x² = 64 - 25
- Subtract: x² = 39
- Isolate <em>x</em>: x = √39
The parameter of a rectangle can be alculated using the following rule:
parameter = 2(length + width)
from the givens:
length = 13 inches
width = 10 inches
so, just substitute with the givens in the equation to calculate the parameter:
parameter = 2(10+13) = 2*23 = 46 inches
<h2>
Step-by-step explanation:</h2>
As per the question,
Let a be any positive integer and b = 4.
According to Euclid division lemma , a = 4q + r
where 0 ≤ r < b.
Thus,
r = 0, 1, 2, 3
Since, a is an odd integer, and
The only valid value of r = 1 and 3
So a = 4q + 1 or 4q + 3
<u>Case 1 :-</u> When a = 4q + 1
On squaring both sides, we get
a² = (4q + 1)²
= 16q² + 8q + 1
= 8(2q² + q) + 1
= 8m + 1 , where m = 2q² + q
<u>Case 2 :-</u> when a = 4q + 3
On squaring both sides, we get
a² = (4q + 3)²
= 16q² + 24q + 9
= 8 (2q² + 3q + 1) + 1
= 8m +1, where m = 2q² + 3q +1
Now,
<u>We can see that at every odd values of r, square of a is in the form of 8m +1.</u>
Also we know, a = 4q +1 and 4q +3 are not divisible by 2 means these all numbers are odd numbers.
Hence , it is clear that square of an odd positive is in form of 8m +1
The triangle on the left appears to be congruent with the triangle on the right. If this observation is actually valid, then x+7 = 2x-5. 12=x Yes, I realize that this doesn't match any of the answer choices, 'tho the 4th choice is the only one that contains "12." Would you please share the instructions for this problem.
