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kozerog [31]
1 year ago
13

A wealthy businessman invests $10,000 and expects a 6.75% rate of return annually. How many years will it take the investment to

reach at least $15,000 in value?Round your answer to the nearest number of years. Do not include units on your answer.
Mathematics
1 answer:
aniked [119]1 year ago
8 0

Answer:

Given that,

A wealthy businessman invests $10,000.

It expects a 6.75% rate of return annually.

To find: the number of years it take the investment to reach at least $15,000 in value.

Explanation:

we know that,

Amount invested at r% rate of interest after t years is,

A=P(1+\frac{r}{100})^t

where P is the initial investment.

Substitute the values we get,

15000=10000(1+\frac{6.75}{100})^t

we get,

\frac{3}{2}=1.0675^t1.5=1.0675^t

we get,

\log_{1.0675}(1.5)=t

Calculating this we get,

t=6.207

Round to the nearest number of years.

we get,

t=6

6 years will it take the investment to reach at least $15,000 in value.

Answer is: 6 years will it take the investment to reach at least $15,000 in value

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In mathematical notation, ∑ means summation. So wherever you see the symbol, you have to sum over all elements in the set. Let's solve the question.

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4 0
3 years ago
The rectangular bar is connected to the support bracket with a 10-mm-diameter pin. The bar width is w = 70 mm and the bar thickn
german

Answer:

P_max = 9.032 KN

Step-by-step explanation:

Given:

- Bar width and each side of bracket w = 70 mm

- Bar thickness and each side of bracket t = 20 mm

- Pin diameter d = 10 mm

- Average allowable bearing stress of (Bar and Bracket) T = 120 MPa

- Average allowable shear stress of pin S = 115 MPa

Find:

The maximum force P that the structure can support.

Solution:

- Bearing Stress in bar:

                                       T = P / A

                                       P = T*A

                                       P = (120) * (0.07*0.02)

                                       P = 168 KN

- Shear stress in pin:

                                        S = P / A

                                        P = S*A

                                        P = (115)*pi*(0.01)^2 / 4

                                        P = 9.032 KN

- Bearing Stress in each bracket:

                                       T = P / 2*A

                                       P = T*A*2

                                       P = 2*(120) * (0.07*0.02)

                                       P = 336 KN

- The maximum force P that this structure can support:

                                      P_max = min (168 , 9.032 , 336)

                                      P_max = 9.032 KN

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