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GuDViN [60]
2 years ago
5

Solve the following proportion for y.y/5 = 7/8Round your answer to the nearest tenth.

Mathematics
1 answer:
Vinvika [58]2 years ago
3 0

The given proportion is expressed as

y/5 = 7/8

If we crossmultiply, it becomes

y * 8 = 7 * 5

8y = 35

y = 35/8

y = 4.375

Rounding to the nearest tenth,

y = 4.4

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Find the measure of ∠x.<br> A) 45° <br> Eliminate<br> B) 46° <br> C) 56° <br> D) 66°
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Event E is defined as the occurrence of one or more of two mutually exclusive events, E1 and E2-. How can you find the probabili
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The product of three and a number is thirty-three. What is the number? N = 11 N = 30 N = 36
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8 0
3 years ago
A population of protozoa develops with a constant relative growth rate of 0.4964 per member per day. On day zero the population
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Answer:

The population size after eight days is about 265

Step-by-step explanation:

This is an example of an exponential growth model. A quantity <em>y</em> that grows or decays at a rate proportional to its size fits in an equation of the form

\frac{dy}{dt}=ky

where k is a positive constant. Its solutions have the form

y=y_{0}e^{kt},

where y_{0} =y(0) is the initial value of y.

The population size can be calculated by using the below formula:

P(t)=P(0)e^{kt} where P(0) is the population on day zero.

Let t be the time in days,

We know from the information given that:

  • k = 0.4964 per member per day and
  • The day zero (t = 0) the population size is 5 (P(0) = 5)

To find the population size after eight days

Substitute P(0) = 5, k=0.4964 in P(t)=P(0)e^{kt}

Then

P(t)=5e^{0.4964\cdot t}

Now we calculate P(t) when t = 8 days

P(8) = 5e^{0.4964\cdot 8}\\P(8) = 5e^{3.9712}\\e^{3.9712}=53.04815\dots \\P(8) = 5 \cdot 53.04815\dots\\P(8) = 265.24075\dots \approx 265

Therefore the population size after eight days is about 265

8 0
3 years ago
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