Question

A football player running at a velocity of 9.0m/s hits the goal post and come to a stop in 0.0sec . calculate his acceleration. (a) find this acceleration in ft/sec ?

Answer 1

The acceleration during uniform motion in ft/sec is -98.42.

We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule

vt = vo + a . t

vt² = vo² + 2a . s

s = vo . t + 1/2 . a . t²

where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.

From the question above, we know that

vo = 9 m/s

t = 0.3 s

vt = 0 m/s

Calculate the acceleration in m/s

vt = vo + at

0 = 9 + a.0.3

a = -9/0.3

a = -30 m/s²

Convert to feet/s

a = -30 m/s

a = -98.42 ft/s

Find more on uniform motion at: brainly.com/question/28040370

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