Answer:
N
Explanation:
= initial velocity of the bullet = 0 m/s
= final velocity of the bullet as it leaves = 443.4 m/s
= acceleration of the bullet
= length of the barrel of the rifle = 0.7 m
the kinematics equation we can use must include the variables in the above list, hence
ms⁻²
= mass of the bullet = 7.9 g = 0.0079 kg
Force exerted on the bullet is given as
N
Answer:
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Explanation:
<u>Elastic Potential Energy
</u>
We find objects like springs that hold potential energy when stretched and they have the capacity to release it when left return to its equilibrium position. The elastic potential energy of a spring of constant k when is stretched a distance x is
The spring constant can be obtained if we know the force N needed to stretch the spring a distance x, by using the Hook's Law
The question provides the information that a force of F = 25 N stretches a spring x= 5 cm = 0.05 m. Using the formula F=kx we can compute the value of k.
The potential energy of the spring in the compressed position (assumed 5 cm as well) if
Answer:
The answer is 'more' as more mass can exert more pressure
Answer:
Psm = 30.66 [Psig]
Explanation:
To solve this problem we will use the ideal gas equation, recall that the ideal gas state equation is always worked with absolute values.
P * v = R * T
where:
P = pressure [Pa]
v = specific volume [m^3/kg]
R = gas constant for air = 0.287 [kJ/kg*K]
T = temperature [K]
<u>For the initial state</u>
<u />
P1 = 24 [Psi] + 14.7 = 165.47[kPa] + 101.325 = 266.8 [kPa] (absolute pressure)
T1 = -2.6 [°C] = - 2.6 + 273 = 270.4 [K] (absolute Temperature)
Therefore we can calculate the specific volume:
v1 = R*T1 / P1
v1 = (0.287 * 270.4) / 266.8
v1 = 0.29 [m^3/kg]
As there are no leaks, the mass and volume are conserved, so the volume in the initial state is equal to the volume in the final state.
V2 = 0.29 [m^3/kg], with this volume and the new temperature, we can calculate the new pressure.
T2 = 43 + 273 = 316 [K]
P2 = R*T2 / V2
P2 = (0.287 * 316) / 0.29
P2 = 312.73 [kPa]
Now calculating the manometric pressure
Psm = 312.73 -101.325 = 211.4 [kPa]
And converting this value to Psig
Psm = 30.66 [Psig]
Answer: It should be the 3rd option down!
Explanation: